Chemistry-
General
Easy

Question

Given that: A(s)→A(ell);ΔH=xA(ell)→A(g)y Thheat osublimatioof A will be-

  1. Zero    
  2. ve    
  3. +ve    
  4.    

The correct answer is: Zero

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Now, the mass of the rod is
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Here, A equals a r e a blank o f blank c r o s s minus s e c t i o n s comma
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Y equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A bullet l blank end fraction blank left parenthesis H e r e comma blank L equals fraction numerator L over denominator 2 end fraction comma l equals e x t e n s i o n right parenthesis
l equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A Y end fraction
or l equals fraction numerator M g L over denominator 2 A Y end fraction
On putting the value of M from Eq.(i), we get
l equals fraction numerator A L rho bullet g L over denominator 2 A Y end fraction
orl equals fraction numerator rho g L to the power of 2 end exponent over denominator 2 Y end fraction

A copper rod of length L and radius ris suspended from the ceiling by one of its ends. What will be elongation of the rod due to its own weight when rho blank a n d blank Y are the density and Young’s modulus of the copper respectively?

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The weight of the rod can be assumed to act at its mid-point.
Now, the mass of the rod is
M equals V rho
M equals A L rho
Here, A equals a r e a blank o f blank c r o s s minus s e c t i o n s comma
L= length of the rod.
Now, we know that the Young’s modulus

Y equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A bullet l blank end fraction blank left parenthesis H e r e comma blank L equals fraction numerator L over denominator 2 end fraction comma l equals e x t e n s i o n right parenthesis
l equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A Y end fraction
or l equals fraction numerator M g L over denominator 2 A Y end fraction
On putting the value of M from Eq.(i), we get
l equals fraction numerator A L rho bullet g L over denominator 2 A Y end fraction
orl equals fraction numerator rho g L to the power of 2 end exponent over denominator 2 Y end fraction
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