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Question

Homolytic bond fission of a covalent single bond gives rise to free radicals. Owing to the presence of an odd electron, free radicals are highly reactive. They have planar to pyramidal geometry depending upon the groups attached to the C-atom having odd electron. Alkyl free radicals are stabilised by hyperconjugation whereas allyl and benzyl free radicals are stabilised by resonance. They are formed as intermediates in the reaction mixture either in the gaseous phase or in non-polar solvents. Addition of HBr to alkenes in presence of peroxide, the substitution of allylic or benzylic hydrogen by ‘Cl’ at high temperature or by ‘Br’ in presence of NBS are examples of reactions involving free radical intermediates.
Arrange the following free radicals in the decreasing order of their stability. C H subscript 2 end subscript equals C H minus stack C with • on top H subscript 2 end subscript semicolon open parentheses C H subscript 3 end subscript close parentheses subscript 3 end subscript stack C with • on top semicolon C H subscript 2 end subscript equals stack C with • on top H semicolon stack C with • on top H subscript 3 end subscript

  1. open parentheses C H subscript 3 end subscript close parentheses subscript 3 end subscript stack C with • on top greater than C H subscript 2 end subscript equals C H minus stack C with • on top H subscript 2 end subscript greater than C H subscript 2 end subscript equals stack C with • on top H greater than stack C with • on top H subscript 3 end subscript    
  2. open parentheses C H subscript 3 end subscript close parentheses subscript 3 end subscript stack C with dot on top greater than C H subscript 2 end subscript equals C H minus stack C H with dot on top subscript 2 end subscript greater than stack C H with dot on top subscript 3 end subscript greater than C H subscript 2 end subscript equals stack C H with dot on top    
  3. C H subscript 2 end subscript equals C H minus stack C H with dot on top subscript 2 end subscript greater than open parentheses C H subscript 3 end subscript close parentheses subscript 3 end subscript stack C with dot on top greater than stack C H with dot on top subscript 3 end subscript greater than C H subscript 2 end subscript equals stack C H with dot on top    
  4. C H subscript 2 end subscript equals C H minus stack C H with dot on top subscript 2 end subscript greater than open parentheses C H subscript 3 end subscript close parentheses subscript 3 end subscript stack C with dot on top greater than C H subscript 2 end subscript equals stack C H with dot on top greater than stack C H with dot on top subscript 3 end subscript    

The correct answer is: C H subscript 2 end subscript equals C H minus stack C H with dot on top subscript 2 end subscript greater than open parentheses C H subscript 3 end subscript close parentheses subscript 3 end subscript stack C with dot on top greater than stack C H with dot on top subscript 3 end subscript greater than C H subscript 2 end subscript equals stack C H with dot on top

Related Questions to study

General
chemistry-

Homolytic bond fission of a covalent single bond gives rise to free radicals. Owing to the presence of an odd electron, free radicals are highly reactive. They have planar to pyramidal geometry depending upon the groups attached to the C-atom having odd electron. Alkyl free radicals are stabilised by hyperconjugation whereas allyl and benzyl free radicals are stabilised by resonance. They are formed as intermediates in the reaction mixture either in the gaseous phase or in non-polar solvents. Addition of HBr to alkenes in presence of peroxide, the substitution of allylic or benzylic hydrogen by ‘Cl’ at high temperature or by ‘Br’ in presence of NBS are examples of reactions involving free radical intermediates.
3, 5–dimethylcyclopentene reacts with N–bromosuccinimide (NBS) in CCl4 in presence of light or peroxide. Identify the product.

Homolytic bond fission of a covalent single bond gives rise to free radicals. Owing to the presence of an odd electron, free radicals are highly reactive. They have planar to pyramidal geometry depending upon the groups attached to the C-atom having odd electron. Alkyl free radicals are stabilised by hyperconjugation whereas allyl and benzyl free radicals are stabilised by resonance. They are formed as intermediates in the reaction mixture either in the gaseous phase or in non-polar solvents. Addition of HBr to alkenes in presence of peroxide, the substitution of allylic or benzylic hydrogen by ‘Cl’ at high temperature or by ‘Br’ in presence of NBS are examples of reactions involving free radical intermediates.
3, 5–dimethylcyclopentene reacts with N–bromosuccinimide (NBS) in CCl4 in presence of light or peroxide. Identify the product.

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What is (B) in the following sequence of reactions?

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Identify (b) in the following sequence of reactions.

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The appropriate reagent for the following transformation is

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A hollow sphere of mass M and radius r is immersed in a tank of water (density rho subscript w end subscript). The sphere would float if it were set free. The sphere is tied to the bottom of the tank by two wires which makes angle 45 to the power of ring operator end exponent with the horizontal as shown in the figure. The tension T1 in the wire is :

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physics-General
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An ideal monoatomic gas is carried around the cycle ABCDA as shown in the figure. The efficiency of the gas cycle is :

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The following graphs shows two isotherms for a fixed mass of an ideal gas. The ratio of r.m.s. speed of the molecules at temperatures T1 and T2 is

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physics-General
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A volume (V)-temperature (T) diagram was obtained when a given mass of gas was heated. During the heating process from state 1 to state 2, the pressure :

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The distribution of relative intensity I(l) of blackbody radiation from a solid body versus the wavelength l is shown in the figure. If the Wien displacement law constant is 2.9 cross times 10 to the power of negative 3 end exponentm K, what is the approximate temperature of the object?

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Five rods of same material and same length are joined as shown. Cross-section of rods ab, ad and bc are A, 2A and 3A respectively. Ends a and c are maintained at temperatures 200°C and 0°C respectively.

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Five rods of same material and same length are joined as shown. Cross-section of rods ab, ad and bc are A, 2A and 3A respectively. Ends a and c are maintained at temperatures 200°C and 0°C respectively.

If x has the value calculated in above question. Then temperature of junction b or d is:

physics-General
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Five rods of same material and same length are joined as shown. Cross-section of rods ab, ad and bc are A, 2A and 3A respectively. Ends a and c are maintained at temperatures 200 to the power of ring operator end exponentC and 0 to the power of ring operator end exponentC respectively.

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For what cross-section x of rod dc there will be no heat flow through rod bd.

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