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IfH2(g)+Cl2(g)→2HCl(g);ΔH°=44Kcal 2Na(s)+2HCl(g)→2NaCl(s)+H2(g);ΔH=–152KcalThe,Na(s)+0.5Cl(g)→NaCl(s);ΔH°=?

  1. 108Kcal    
  2. 196Kcal    
  3. 98Kcal    
  4. 54Kcal    

The correct answer is: –98Kcal

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