Chemistry-
General
Easy

Question

In body-centered cubic lattice given below, the three distances AB, AC, and AA'' are

  1. a comma square root of 2 a comma fraction numerator square root of 3 a over denominator 2 end fraction    
  2. a comma fraction numerator square root of 3 a over denominator 2 end fraction comma square root of 2 a    
  3. fraction numerator square root of 3 a over denominator 2 end fraction comma square root of 2 a comma a    
  4. a comma fraction numerator a over denominator square root of 2 end fraction comma fraction numerator square root of 3 a over denominator 2 end fraction    

The correct answer is: a comma square root of 2 a comma fraction numerator square root of 3 a over denominator 2 end fraction


    1. Edge lengthequals blank A B equals A D equals B C equals C D equals a
    2.A C equals square root of 2 a
    3.A G (body diagonal)equals square root of 3 a
    Therefore A A to the power of ´ end exponent equals A G divided by 2 equals fraction numerator square root of 3 over denominator 2 end fraction a

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