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chemistry-

chemistry-General
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chemistry-General
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What will be the most probable product when compound ‘X’ is treated with two equivalents of NaOH,

What will be the most probable product when compound ‘X’ is treated with two equivalents of NaOH,

chemistry-General
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Aniline reacts with mixed acid (conc. HNO3 and conc. H2SO4 ) at 288 K to give P (51%), Q (47%) and R (51%), Q(47%) and R (2%). The major product(s) of the following reaction sequence is/are

Aniline reacts with mixed acid (conc. HNO3 and conc. H2SO4 ) at 288 K to give P (51%), Q (47%) and R (51%), Q(47%) and R (2%). The major product(s) of the following reaction sequence is/are

chemistry-General
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The major product of the following reaction is

The major product of the following reaction is

chemistry-General
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In the following reaction sequences V and W are respectively :

In the following reaction sequences V and W are respectively :

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GivenC left parenthesis s right parenthesis plus O subscript 2 end subscript left parenthesis g right parenthesis C O subscript 2 end subscript left parenthesis g right parenthesis plus 94.2Kcal H subscript 2 end subscript left parenthesis g right parenthesis plus 1 divided by 2 O subscript 2 end subscript left parenthesis g right parenthesis rightwards arrow stack H subscript 2 end subscript O with _ below left parenthesis l right parenthesis plus 68.3Kcal C H subscript 4 end subscript left parenthesis g right parenthesis plus 2 O subscript 2 end subscript left parenthesis g right parenthesis times C O subscript 2 end subscript left parenthesis g right parenthesis plus 2 stack stack H with _ below subscript 2 end subscript O with _ below left parenthesis l right parenthesis plus 210.8Kcal thheaoformatioomethane in Kcawilbe-

GivenC left parenthesis s right parenthesis plus O subscript 2 end subscript left parenthesis g right parenthesis C O subscript 2 end subscript left parenthesis g right parenthesis plus 94.2Kcal H subscript 2 end subscript left parenthesis g right parenthesis plus 1 divided by 2 O subscript 2 end subscript left parenthesis g right parenthesis rightwards arrow stack H subscript 2 end subscript O with _ below left parenthesis l right parenthesis plus 68.3Kcal C H subscript 4 end subscript left parenthesis g right parenthesis plus 2 O subscript 2 end subscript left parenthesis g right parenthesis times C O subscript 2 end subscript left parenthesis g right parenthesis plus 2 stack stack H with _ below subscript 2 end subscript O with _ below left parenthesis l right parenthesis plus 210.8Kcal thheaoformatioomethane in Kcawilbe-

chemistry-General
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A set of (2n + 1) elements is given. The no. of subsets of the set which contain atmost n elements -

A set of (2n + 1) elements is given. The no. of subsets of the set which contain atmost n elements -

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  under Hofmann conditions will give :

  under Hofmann conditions will give :

chemistry-General
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General
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 Which step is rate determining ste

 Which step is rate determining ste

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Which reagent (X) is used to convert I to II

Which reagent (X) is used to convert I to II

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An organic compound A upon reacting with NH3 gives B. On heating B gives C. C in presence of KOH reacts with Br2 to given CH3CH2NH2 . A is :

An organic compound A upon reacting with NH3 gives B. On heating B gives C. C in presence of KOH reacts with Br2 to given CH3CH2NH2 . A is :

chemistry-General
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General
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If r, s, t are prime numbers and p, q are the positive integers such that the LCM of p, q is r squared s to the power of 4 t squared, then the number of ordered pair (p, q) is-

Be careful about selecting the r s and t for this particular problem. Because number ways for each selection of r, s and t there are 3 cases. Because there are two values given

p, q . Hence to calculate the total number of ways is to multiply the number of ways for r, number of ways for s and number of ways for t. So, in this way to solve this particular type of problem.

If r, s, t are prime numbers and p, q are the positive integers such that the LCM of p, q is r squared s to the power of 4 t squared, then the number of ordered pair (p, q) is-

Maths-General

Be careful about selecting the r s and t for this particular problem. Because number ways for each selection of r, s and t there are 3 cases. Because there are two values given

p, q . Hence to calculate the total number of ways is to multiply the number of ways for r, number of ways for s and number of ways for t. So, in this way to solve this particular type of problem.

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A rectangle has sides of (2m – 1) & (2n – 1) units as shown in the figure composed of squares having edge length one unit then no. of rectangles which have odd unit length

A rectangle has sides of (2m – 1) & (2n – 1) units as shown in the figure composed of squares having edge length one unit then no. of rectangles which have odd unit length

Maths-General
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Observe the esterification mechanisms for primary and tertiary alcohols
Type-1:

Type-2: 
Mechanism: 

In the above reaction (P) and (Q) are respectively :

Observe the esterification mechanisms for primary and tertiary alcohols
Type-1:

Type-2: 
Mechanism: 

In the above reaction (P) and (Q) are respectively :

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