Chemistry-
General
Easy

Question

The following carbohydrate is

  1. a ketohexose    
  2. an aldohexose    
  3. an alpha -furanose    
  4. an alpha -pyranose    

The correct answer is: an alpha -furanose

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Related Questions to study

General
chemistry-

The correct statement(s) about the following sugars X and Y is(are) :

The correct statement(s) about the following sugars X and Y is(are) :

chemistry-General
General
physics-

A copper rod of length L and radius ris suspended from the ceiling by one of its ends. What will be elongation of the rod due to its own weight when rho blank a n d blank Y are the density and Young’s modulus of the copper respectively?

The weight of the rod can be assumed to act at its mid-point.
Now, the mass of the rod is
M equals V rho
M equals A L rho
Here, A equals a r e a blank o f blank c r o s s minus s e c t i o n s comma
L= length of the rod.
Now, we know that the Young’s modulus

Y equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A bullet l blank end fraction blank left parenthesis H e r e comma blank L equals fraction numerator L over denominator 2 end fraction comma l equals e x t e n s i o n right parenthesis
l equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A Y end fraction
or l equals fraction numerator M g L over denominator 2 A Y end fraction
On putting the value of M from Eq.(i), we get
l equals fraction numerator A L rho bullet g L over denominator 2 A Y end fraction
orl equals fraction numerator rho g L to the power of 2 end exponent over denominator 2 Y end fraction

A copper rod of length L and radius ris suspended from the ceiling by one of its ends. What will be elongation of the rod due to its own weight when rho blank a n d blank Y are the density and Young’s modulus of the copper respectively?

physics-General
The weight of the rod can be assumed to act at its mid-point.
Now, the mass of the rod is
M equals V rho
M equals A L rho
Here, A equals a r e a blank o f blank c r o s s minus s e c t i o n s comma
L= length of the rod.
Now, we know that the Young’s modulus

Y equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A bullet l blank end fraction blank left parenthesis H e r e comma blank L equals fraction numerator L over denominator 2 end fraction comma l equals e x t e n s i o n right parenthesis
l equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A Y end fraction
or l equals fraction numerator M g L over denominator 2 A Y end fraction
On putting the value of M from Eq.(i), we get
l equals fraction numerator A L rho bullet g L over denominator 2 A Y end fraction
orl equals fraction numerator rho g L to the power of 2 end exponent over denominator 2 Y end fraction
General
physics-

The value of force constant between the applied elastic force F and displacement will be

Force constant, K equals tan invisible function application 30 degree equals 1 divided by square root of 3

The value of force constant between the applied elastic force F and displacement will be

physics-General
Force constant, K equals tan invisible function application 30 degree equals 1 divided by square root of 3
General
physics-

A student plots a graph from his reading on the determination of Young’s modulus of a metal wire but forgets to label. The quantities on X and Y axes may be respectively

A student plots a graph from his reading on the determination of Young’s modulus of a metal wire but forgets to label. The quantities on X and Y axes may be respectively

physics-General
General
physics-

If the ratio of lengths, radii and Young’s modulus of steel and brass wires shown in the figure are a comma blank band c, respectively. The ratio between the increase in lengths of brass and steel wires would be

Given, fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction equals a comma fraction numerator r subscript 1 end subscript over denominator r subscript 2 end subscript end fraction equals b comma fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals c

Let Young’s modulus of steel be Y subscript 1 end subscript, and that of brass be Y subscript 2 end subscript
therefore Y subscript 1 end subscript equals fraction numerator F subscript 1 end subscript l subscript 1 end subscript over denominator A subscript 1 end subscript increment l subscript 1 end subscript end fraction (i)
and Y subscript 2 end subscript equals fraction numerator F subscript 2 end subscript l subscript 2 end subscript over denominator A subscript 2 end subscript increment l subscript 2 end subscript end fraction(ii)
Dividing Equation (i) by Equation (ii), we get
fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals fraction numerator F subscript 1 end subscript. A subscript 2 end subscript. l subscript 1 end subscript. increment l subscript 2 end subscript over denominator F subscript 2 end subscript. A subscript 1 end subscript. l subscript 2 end subscript. increment l subscript 1 end subscript end fraction(iii)
Force on steel wire from free body diagram
T equals F subscript 1 end subscript equals left parenthesis 2 g right parenthesis Newton
Force on brass wire from free body diagram
F subscript 2 end subscript equals T subscript 1 end subscript superscript ´ ´ end superscript equals T plus 2 g equals 4 g Newton
Now, putting the value of F subscript 1 end subscript comma F subscript 2 end subscript comma in Equation (iii), we get
fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals open parentheses fraction numerator 2 g over denominator 4 g end fraction close parentheses. open parentheses fraction numerator pi r subscript 2 end subscript superscript 2 end superscript over denominator pi r subscript 1 end subscript superscript 2 end superscript end fraction close parentheses. open square brackets fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction close square brackets. open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses equals fraction numerator 1 over denominator 2 end fraction open parentheses fraction numerator 1 over denominator b subscript 2 end subscript end fraction close parentheses. a open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses

If the ratio of lengths, radii and Young’s modulus of steel and brass wires shown in the figure are a comma blank band c, respectively. The ratio between the increase in lengths of brass and steel wires would be

physics-General
Given, fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction equals a comma fraction numerator r subscript 1 end subscript over denominator r subscript 2 end subscript end fraction equals b comma fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals c

Let Young’s modulus of steel be Y subscript 1 end subscript, and that of brass be Y subscript 2 end subscript
therefore Y subscript 1 end subscript equals fraction numerator F subscript 1 end subscript l subscript 1 end subscript over denominator A subscript 1 end subscript increment l subscript 1 end subscript end fraction (i)
and Y subscript 2 end subscript equals fraction numerator F subscript 2 end subscript l subscript 2 end subscript over denominator A subscript 2 end subscript increment l subscript 2 end subscript end fraction(ii)
Dividing Equation (i) by Equation (ii), we get
fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals fraction numerator F subscript 1 end subscript. A subscript 2 end subscript. l subscript 1 end subscript. increment l subscript 2 end subscript over denominator F subscript 2 end subscript. A subscript 1 end subscript. l subscript 2 end subscript. increment l subscript 1 end subscript end fraction(iii)
Force on steel wire from free body diagram
T equals F subscript 1 end subscript equals left parenthesis 2 g right parenthesis Newton
Force on brass wire from free body diagram
F subscript 2 end subscript equals T subscript 1 end subscript superscript ´ ´ end superscript equals T plus 2 g equals 4 g Newton
Now, putting the value of F subscript 1 end subscript comma F subscript 2 end subscript comma in Equation (iii), we get
fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals open parentheses fraction numerator 2 g over denominator 4 g end fraction close parentheses. open parentheses fraction numerator pi r subscript 2 end subscript superscript 2 end superscript over denominator pi r subscript 1 end subscript superscript 2 end superscript end fraction close parentheses. open square brackets fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction close square brackets. open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses equals fraction numerator 1 over denominator 2 end fraction open parentheses fraction numerator 1 over denominator b subscript 2 end subscript end fraction close parentheses. a open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses
General
chemistry-

Salicin (structure given below) is a glycoside, found in the bark of willow tree, used in relieving pain. Observe the following reaction of salicin

The correct statement (s) is (are) :

Salicin (structure given below) is a glycoside, found in the bark of willow tree, used in relieving pain. Observe the following reaction of salicin

The correct statement (s) is (are) :

chemistry-General
General
physics-

Which one of the following is the Young’s modules (in N divided by m to the power of 2 end exponent right parenthesis for the wire having the stress-strain curve shown in the figure

Young’s modulus is defined only in elastic region and
Y equals fraction numerator S t r e s s over denominator S t r a i n end fraction equals fraction numerator 8 cross times 10 to the power of 7 end exponent over denominator 4 cross times 10 to the power of negative 4 end exponent end fraction equals 2 cross times 10 to the power of 11 end exponent N divided by m to the power of 2 end exponent

Which one of the following is the Young’s modules (in N divided by m to the power of 2 end exponent right parenthesis for the wire having the stress-strain curve shown in the figure

physics-General
Young’s modulus is defined only in elastic region and
Y equals fraction numerator S t r e s s over denominator S t r a i n end fraction equals fraction numerator 8 cross times 10 to the power of 7 end exponent over denominator 4 cross times 10 to the power of negative 4 end exponent end fraction equals 2 cross times 10 to the power of 11 end exponent N divided by m to the power of 2 end exponent
General
physics-

The diagram shows the change x in the length of a thin uniform wire caused by the application of stress F at two different temperatures T subscript 1 end subscriptand T subscript 2 end subscript. The variation shown suggest that

Elasticity of wire decreases at high temperature i. e. at higher temperature slope of graph will be less
So we can say that T subscript 1 end subscript greater than T subscript 2 end subscript

The diagram shows the change x in the length of a thin uniform wire caused by the application of stress F at two different temperatures T subscript 1 end subscriptand T subscript 2 end subscript. The variation shown suggest that

physics-General
Elasticity of wire decreases at high temperature i. e. at higher temperature slope of graph will be less
So we can say that T subscript 1 end subscript greater than T subscript 2 end subscript
General
chemistry-

IHf ofICl(g),Cl(g),andI(g)is17.57,121.34and 106.96Jmol1respectively.Thenbonddissociation energyofIClbondis-

IHf ofICl(g),Cl(g),andI(g)is17.57,121.34and 106.96Jmol1respectively.Thenbonddissociation energyofIClbondis-

chemistry-General
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chemistry-

Calculateenthalpychangeofthefollowingreaction H2C=CH2(g)+H2(g)→H3CCH3(g) ThebondenergiesofC–H,C–C,C=C,H–Hare414, 347,615and435KJmol1respectively-

Calculateenthalpychangeofthefollowingreaction H2C=CH2(g)+H2(g)→H3CCH3(g) ThebondenergiesofC–H,C–C,C=C,H–Hare414, 347,615and435KJmol1respectively-

chemistry-General
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chemistry-

HeatevolvedinthereactionH2+Cl2 →2HClis 182KJ.BondenergiesofHH anCl–Clare430 and242KJ/morespectively.ThHCbond energy is-

HeatevolvedinthereactionH2+Cl2 →2HClis 182KJ.BondenergiesofHH anCl–Clare430 and242KJ/morespectively.ThHCbond energy is-

chemistry-General
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chemistry-

Among thfollowinfowhich reactioheat of reactiorepresents bond energof HCl

Among thfollowinfowhich reactioheat of reactiorepresents bond energof HCl

chemistry-General
General
physics

The range of a galvanometer of resistance G ohm is V  wolt. The resistance required to be connected in series with it in order to convert it into voltmeter of range  n V volt will be........

The range of a galvanometer of resistance G ohm is V  wolt. The resistance required to be connected in series with it in order to convert it into voltmeter of range  n V volt will be........

physicsGeneral
General
physics

A galvanometer with resistance 100Ω  is converted into an ammeter with a resistance of 0.1. The galvanometer shows full scale deflection with current of 100μA. Then what will be the minimum current in the circuit for fall scale deflection of galvanometer?

A galvanometer with resistance 100Ω  is converted into an ammeter with a resistance of 0.1. The galvanometer shows full scale deflection with current of 100μA. Then what will be the minimum current in the circuit for fall scale deflection of galvanometer?

physicsGeneral
General
physics

A galvanometer of resistance 200Ω  gives full scale deflection for a current of  10 to the power of negative 3 end exponentA. To convert it into an anmeter capable of measuring upto  1A. What resistance should be connected in parallel with it ?

A galvanometer of resistance 200Ω  gives full scale deflection for a current of  10 to the power of negative 3 end exponentA. To convert it into an anmeter capable of measuring upto  1A. What resistance should be connected in parallel with it ?

physicsGeneral