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Question

Thfour quantunumberfothvalence shell electron of last electron of sodium (Z=11is

  1. n=2,l=1,m=–1,s=–fraction numerator 1 over denominator 2 end fraction    
  2. n=3, l=0,m=0,s=+fraction numerator 1 over denominator 2 end fraction    
  3. n=3, l=0,m=–0,s=±fraction numerator 1 over denominator 2 end fraction    
  4. n=3,l=2,m=2,s=+fraction numerator 1 over denominator 2 end fraction    

The correct answer is: n=3, l=0,m=0,s=+fraction numerator 1 over denominator 2 end fraction

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