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Chemistry-

General

Easy

Question

The IUPAC name of

1, 1-diethyl-2, 2-dimethylpentane
4, 4-dimethyl-5, 5-diethylpentane
5, 5-diethyl-4, 4-dimethylpentane
3-ethyl-4, 4-dimethylheptane

The correct answer is: 3-ethyl-4, 4-dimethylheptane

3, ethyl 4, 4 di methyl he ptane.

Related Questions to study

The IUPAC name of the compound shown below is

3.3 di ethyl pentane

The IUPAC name of the compound shown below is

chemistry-General

3.3 di ethyl pentane

The IUPAC name of the compound

3, 3 dimethyl 1-cyclohexanol

The IUPAC name of the compound

chemistry-General

3, 3 dimethyl 1-cyclohexanol

$cos space 56 to the power of ring operator plus cos space 58 to the power of ring operator minus cos space 66 to the power of ring operator minus 4 cos space 28 to the power of ring operator cos space 29 to the power of ring operator sin space 33 to the power of ring operator$

$cos space 56 to the power of ring operator plus cos space 58 to the power of ring operator minus cos space 66 to the power of ring operator minus 4 cos space 28 to the power of ring operator cos space 29 to the power of ring operator sin space 33 to the power of ring operator$

parallel

Which of the following compounds has wrong IUPAC name?

2 - methyl 3 - butanol is wrong

Which of the following compounds has wrong IUPAC name?

chemistry-General

2 - methyl 3 - butanol is wrong

2- chloro 4- methyl 2 - pentene.

chemistry-General

2- chloro 4- methyl 2 - pentene.

What is the IUPAC name of

1 - chloro 2- methyl 2- meth 1 butane

What is the IUPAC name of

chemistry-General

1 - chloro 2- methyl 2- meth 1 butane

parallel

If $fraction numerator tan space left parenthesis alpha plus beta minus gamma right parenthesis over denominator tan space left parenthesis alpha minus beta plus gamma right parenthesis end fraction equals fraction numerator tan begin display style space end style gamma over denominator tan begin display style space end style beta end fraction left parenthesis beta not equal to gamma right parenthesis$ then $sin space 2 alpha plus sin space 2 beta plus sin space 2 gamma$ =

If $fraction numerator tan space left parenthesis alpha plus beta minus gamma right parenthesis over denominator tan space left parenthesis alpha minus beta plus gamma right parenthesis end fraction equals fraction numerator tan begin display style space end style gamma over denominator tan begin display style space end style beta end fraction left parenthesis beta not equal to gamma right parenthesis$ then $sin space 2 alpha plus sin space 2 beta plus sin space 2 gamma$ =

If $fraction numerator sin cubed space theta minus cos cubed space theta over denominator sin space theta minus cos space theta end fraction minus fraction numerator cos begin display style space end style theta over denominator square root of open parentheses 1 plus cot squared space theta close parentheses end root end fraction$ -2 tan $theta cot space theta equals negative 1 comma theta element of left square bracket 0 comma 2 pi right square bracket$ then

If $fraction numerator sin cubed space theta minus cos cubed space theta over denominator sin space theta minus cos space theta end fraction minus fraction numerator cos begin display style space end style theta over denominator square root of open parentheses 1 plus cot squared space theta close parentheses end root end fraction$ -2 tan $theta cot space theta equals negative 1 comma theta element of left square bracket 0 comma 2 pi right square bracket$ then

If $theta equals p over q$ and $theta equals 3 ϕ open parentheses 0 less than theta less than pi over 2 close parentheses$ ,then $fraction numerator p over denominator sin invisible function application ϕ end fraction minus fraction numerator q over denominator cos invisible function application ϕ end fraction equals$

If $theta equals p over q$ and $theta equals 3 ϕ open parentheses 0 less than theta less than pi over 2 close parentheses$ ,then $fraction numerator p over denominator sin invisible function application ϕ end fraction minus fraction numerator q over denominator cos invisible function application ϕ end fraction equals$

parallel

The reaction (CH₃)₃ C - Br → (CH₃)₃ $stack C with plus on top plus B r to the power of minus end exponent$ is an example of

The reaction (CH₃)₃ C - Br → (CH₃)₃ $stack C with plus on top plus B r to the power of minus end exponent$ is an example of

chemistry-General

$Na subscript 2 straight B subscript 4 straight O subscript 7 times 10 straight H subscript 2 straight O not stretchy rightwards arrow with straight capital delta on top NaBO subscript 2 plus left parenthesis A right parenthesis plus straight H subscript 2 straight O left parenthesis A right parenthesis plus MnO not stretchy rightwards arrow with straight capital delta on top left parenthesis B right parenthesis$ (A) and (B) are

$Na subscript 2 straight B subscript 4 straight O subscript 7 times 10 straight H subscript 2 straight O not stretchy rightwards arrow with straight capital delta on top NaBO subscript 2 plus left parenthesis A right parenthesis plus straight H subscript 2 straight O left parenthesis A right parenthesis plus MnO not stretchy rightwards arrow with straight capital delta on top left parenthesis B right parenthesis$ (A) and (B) are

chemistry-General

If $fraction numerator a x over denominator cos invisible function application theta end fraction plus fraction numerator b y over denominator sin invisible function application theta end fraction equals open parentheses a squared minus b squared close parentheses$ ,and $fraction numerator a x sin invisible function application theta over denominator cos squared invisible function application theta end fraction minus fraction numerator b y cos invisible function application theta over denominator sin squared invisible function application theta end fraction equals 0$ ,then $left parenthesis a x right parenthesis to the power of 2 divided by 3 end exponent plus left parenthesis b y right parenthesis to the power of 2 divided by 3 end exponent equals$

If $fraction numerator a x over denominator cos invisible function application theta end fraction plus fraction numerator b y over denominator sin invisible function application theta end fraction equals open parentheses a squared minus b squared close parentheses$ ,and $fraction numerator a x sin invisible function application theta over denominator cos squared invisible function application theta end fraction minus fraction numerator b y cos invisible function application theta over denominator sin squared invisible function application theta end fraction equals 0$ ,then $left parenthesis a x right parenthesis to the power of 2 divided by 3 end exponent plus left parenthesis b y right parenthesis to the power of 2 divided by 3 end exponent equals$

parallel

If $A plus cos invisible function application B plus cos invisible function application C equals 0$ then $cos invisible function application 3 straight A plus cos invisible function application 3 straight B plus cos invisible function application 3 straight C$

If $A plus cos invisible function application B plus cos invisible function application C equals 0$ then $cos invisible function application 3 straight A plus cos invisible function application 3 straight B plus cos invisible function application 3 straight C$

The value of $fraction numerator 3 plus cot invisible function application 76 to the power of ring operator cot invisible function application 16 to the power of ring operator over denominator cot invisible function application 76 to the power of ring operator plus cot invisible function application 16 to the power of ring operator end fraction$ is

The value of $fraction numerator 3 plus cot invisible function application 76 to the power of ring operator cot invisible function application 16 to the power of ring operator over denominator cot invisible function application 76 to the power of ring operator plus cot invisible function application 16 to the power of ring operator end fraction$ is

If are four angles then $sin invisible function application left parenthesis A minus B right parenthesis times cos invisible function application left parenthesis A plus B right parenthesis plus sin invisible function application left parenthesis B minus C right parenthesis cos invisible function application left parenthesis B plus C right parenthesis plus sin invisible function application left parenthesis C minus D right parenthesis$ . $cos invisible function application left parenthesis C plus D right parenthesis plus sin invisible function application left parenthesis D minus A right parenthesis times cos invisible function application left parenthesis D plus A right parenthesis equals$

If are four angles then $sin invisible function application left parenthesis A minus B right parenthesis times cos invisible function application left parenthesis A plus B right parenthesis plus sin invisible function application left parenthesis B minus C right parenthesis cos invisible function application left parenthesis B plus C right parenthesis plus sin invisible function application left parenthesis C minus D right parenthesis$ . $cos invisible function application left parenthesis C plus D right parenthesis plus sin invisible function application left parenthesis D minus A right parenthesis times cos invisible function application left parenthesis D plus A right parenthesis equals$

parallel

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