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The IUPAC name of the given compound
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  1. 2–Bromo–4–carbamoyl–5–chloroformyl– 3–formyl hexanoic acid    
  2. 5–Bromo–3–carbamoyl–2–chloroformyl– 4–formyl hexanoic acid    
  3. 4–Formyl–2–chloroformyl–3–carbamoyl – 5 –bromo hexanoic acid    
  4. 2–chloroformyl–3–carbamoyl–4–Formyl –5–bromo hexanoic acid    

The correct answer is: 5–Bromo–3–carbamoyl–2–chloroformyl– 4–formyl hexanoic acid

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