Chemistry-
General
Easy

Question

The most suitable reagent of r the conversion of RCH2OH → RCHO is

  1. KMnO4    
  2. K2Cr2O7    
  3. CrO3    
  4. PCC (pyridine chloro chromate )    

The correct answer is: PCC (pyridine chloro chromate )


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    Which alkali metal floats over cold water without any reaction?

    4, Na, k all are less denses them water among these first group Li is very less reactive

    Which alkali metal floats over cold water without any reaction?

    chemistry-General
    4, Na, k all are less denses them water among these first group Li is very less reactive
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    The radius of germanium (G e) nuclide is measured to be twice the radius of scriptbase B e end scriptbase presubscript 4 end presubscript presuperscript 9 end presuperscript. The number of nucleons in Ge are

    Let radius of scriptbase B e end scriptbase presubscript 4 end presubscript presuperscript 9 end presuperscript nucleus be r. Then radius of germanium (Ge) nucleus will be2 r.
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    R equals R subscript 0 end subscript A to the power of 1 divided by 3 end exponent
    therefore fraction numerator R subscript 1 end subscript over denominator R subscript 2 end subscript end fraction equals open parentheses fraction numerator A subscript 1 end subscript over denominator A subscript 2 end subscript end fraction close parentheses to the power of 1 divided by 3 end exponent
    rightwards double arrow fraction numerator r over denominator 2 r end fraction equals open parentheses fraction numerator 9 over denominator A to the power of 2 end exponent end fraction close parentheses to the power of 1 divided by 3 end exponent left parenthesis because A subscript 1 end subscript equals 9 right parenthesis
    rightwards double arrow blank open parentheses fraction numerator 1 over denominator 2 end fraction close parentheses to the power of 3 end exponent equals fraction numerator 9 over denominator A to the power of 2 end exponent end fraction
    Hence,A subscript 2 end subscript equals 9 blank cross times blank open parentheses 2 close parentheses to the power of 3 end exponent blank equals 9 cross times 8 equals 72
    Thus, in germanium (G e) nucleus number of nucleons is 72.

    The radius of germanium (G e) nuclide is measured to be twice the radius of scriptbase B e end scriptbase presubscript 4 end presubscript presuperscript 9 end presuperscript. The number of nucleons in Ge are

    physics-General
    Let radius of scriptbase B e end scriptbase presubscript 4 end presubscript presuperscript 9 end presuperscript nucleus be r. Then radius of germanium (Ge) nucleus will be2 r.
    Radius ofnucleus is given by
    R equals R subscript 0 end subscript A to the power of 1 divided by 3 end exponent
    therefore fraction numerator R subscript 1 end subscript over denominator R subscript 2 end subscript end fraction equals open parentheses fraction numerator A subscript 1 end subscript over denominator A subscript 2 end subscript end fraction close parentheses to the power of 1 divided by 3 end exponent
    rightwards double arrow fraction numerator r over denominator 2 r end fraction equals open parentheses fraction numerator 9 over denominator A to the power of 2 end exponent end fraction close parentheses to the power of 1 divided by 3 end exponent left parenthesis because A subscript 1 end subscript equals 9 right parenthesis
    rightwards double arrow blank open parentheses fraction numerator 1 over denominator 2 end fraction close parentheses to the power of 3 end exponent equals fraction numerator 9 over denominator A to the power of 2 end exponent end fraction
    Hence,A subscript 2 end subscript equals 9 blank cross times blank open parentheses 2 close parentheses to the power of 3 end exponent blank equals 9 cross times 8 equals 72
    Thus, in germanium (G e) nucleus number of nucleons is 72.
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    The approximate nuclear radius is proportional to (A is the mass number and Z the atomic number)

    Experimentally it is found that the volume of a nucleus is directly proportional to its mass number. From this it is concluded that the density of each nucleus is uniform, it does not depend on the size of the nucleus.
    It the nucleus is assumed to be a sphere of radius R and its mass number is A, then volume of nucleusV equals fraction numerator 4 over denominator 3 end fraction pi R to the power of 3 end exponent.
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    OrR blank proportional to blank A to the power of 1 divided by 3 end exponent
    i e commathe radius of nucleus is directly proportional to the cube root(or fraction numerator 1 over denominator 3 end fraction power) of its mass number A.
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    R equals R subscript 0 end subscript A to the power of 1 divided by 3 end exponent
    therefore blank R proportional to blank A to the power of 1 divided by 3 end exponent

    The approximate nuclear radius is proportional to (A is the mass number and Z the atomic number)

    physics-General
    Experimentally it is found that the volume of a nucleus is directly proportional to its mass number. From this it is concluded that the density of each nucleus is uniform, it does not depend on the size of the nucleus.
    It the nucleus is assumed to be a sphere of radius R and its mass number is A, then volume of nucleusV equals fraction numerator 4 over denominator 3 end fraction pi R to the power of 3 end exponent.
    Thus, fraction numerator 4 over denominator 3 end fraction pi R to the power of 3 end exponent proportional to blank A blank o r blank R to the power of 3 end exponent proportional to blank A
    OrR blank proportional to blank A to the power of 1 divided by 3 end exponent
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    R equals R subscript 0 end subscript A to the power of 1 divided by 3 end exponent
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    The energy levels of the hydrogen spectrum is shown in figure. There are some transition A comma B comma C comma D and E.Transition A comma B and C respectively represent

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    Transition B (n equals 5 to n equals 2) : Third spectral line of Balmer series
    Transition C (n equals 5 to n equals 3) : Second spectral line of Paschen series

    The energy levels of the hydrogen spectrum is shown in figure. There are some transition A comma B comma C comma D and E.Transition A comma B and C respectively represent

    physics-General
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    Transition B (n equals 5 to n equals 2) : Third spectral line of Balmer series
    Transition C (n equals 5 to n equals 3) : Second spectral line of Paschen series
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    A-mRNA, B-nucleus, C-Hormone receptor complex, D-hormone
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    biologyGeneral
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    biologyGeneral
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    biologyGeneral
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    VII)Site for active ribosomal RNA synthesis
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    iii) Power house of the cell – H
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    v) Increase the surface area for the absorption materials – N
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    I)The structure replicates during mitosis and generates the spindle
    II)Major site for synthesis of lipid
    III)Power house of the cell
    IV)store house of digestive enzyme
    V)Increase the surface are for the absorption of materials
    VI)Site of glycolysis
    VII)Site for active ribosomal RNA synthesis
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    biologyGeneral
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    ii) Major site for synthesis of lipid – B
    iii) Power house of the cell – H
    iv) Store house of digestive enzyme – J
    v) Increase the surface area for the absorption materials – N
    vi) Site of glycolysis – F
    vii) Site for active ribosomal RNA synthesis – D
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    A-Plasma membrane, B-Interdoublet bridge, C-Central microtubule and D-Radial spoke
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    maths-General