Chemistry-

#### The ratio of wave lengths of first line of Lymen series in Li^{+2} and first line of Lymen series in deuterium(_{1}H^{2})is:

Chemistry-General

- 9:1
- 1:4
- 4:1
- 1:9

#### Answer:The correct answer is: 1:9

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#### The four quantum numbers for the valence shell electron of last electron of sodium (Z=11) is

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maths-

#### Equation of a circle with centre (4, 3) touching the circle is

Let the circle touching the circle x

The equation of the common tangent is S

i.e. 8x + 6y–1–k = 0

This is a tangent to the circle x

Hence ± 1 =

Þ k+1 = ± 10 Þ k = –11 or 9

Therefore the circles are x

Hence (d) are the correct answers.

^{2 }+ y^{2}= 1, be x^{2 }+ y^{2 }– 8x – 6y + k = 0,The equation of the common tangent is S

_{1}– S_{2}= 0i.e. 8x + 6y–1–k = 0

This is a tangent to the circle x

^{2}+y^{2}= 1.Hence ± 1 =

Þ k+1 = ± 10 Þ k = –11 or 9

Therefore the circles are x

^{2}+y^{2}–8x–6y+9 = 0 and x^{2}+y^{2}–8x–6y–11 = 0Hence (d) are the correct answers.

#### Equation of a circle with centre (4, 3) touching the circle is

maths-General

Let the circle touching the circle x

The equation of the common tangent is S

i.e. 8x + 6y–1–k = 0

This is a tangent to the circle x

Hence ± 1 =

Þ k+1 = ± 10 Þ k = –11 or 9

Therefore the circles are x

Hence (d) are the correct answers.

^{2 }+ y^{2}= 1, be x^{2 }+ y^{2 }– 8x – 6y + k = 0,The equation of the common tangent is S

_{1}– S_{2}= 0i.e. 8x + 6y–1–k = 0

This is a tangent to the circle x

^{2}+y^{2}= 1.Hence ± 1 =

Þ k+1 = ± 10 Þ k = –11 or 9

Therefore the circles are x

^{2}+y^{2}–8x–6y+9 = 0 and x^{2}+y^{2}–8x–6y–11 = 0Hence (d) are the correct answers.