Chemistry-
General
Easy
Question
Theheatevolvedduringthecombustionof112litre of water gas(mixtureofequalvolumeofH2andCO)
is: Given
H2(g)+1/2O2(g)=H2O(g);ΔH=–241.8KJ
CO(g)+1/2O2(g)=CO2(g);ΔH=–283KJ</span
- 241.8KJ
- 283KJ
- 1312KJ
- 1586KJ
The correct answer is: 1312KJ
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