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Chemistry-

General

Easy

Question

WhatweightofHNO3isneededtoconvert 62gmofP₄ inH₃PO₄ in the reaction? P₄ +HNO₃ →H₃PO₄ +NO₂ +H₂O

63gm
630gm
315gm
126gm

The correct answer is: 630gm

Related Questions to study

The distance of the centre of mass of the $T$ -shaped plate from $O$ is

Co-ordinate of CM is given by

X subscript C M end subscript equals fraction numerator m subscript 1 end subscript x subscript 1 end subscript plus m subscript 2 end subscript x subscript 2 end subscript over denominator m subscript 1 end subscript plus m subscript 2 end subscript end fraction

A

B

as two bodies of same system

m subscript 1 end subscript equals l cross times b cross times sigma equals 8 cross times 2 cross times sigma equals 16 sigma

m subscript 2 end subscript equals l cross times b cross times sigma equals 6 cross times 2 cross times sigma equals 12 sigma

O

x subscript 1 end subscript equals 1 blank m comma blank x subscript 2 end subscript equals 2 plus 3 equals 5 blank m

therefore X subscript C M end subscript equals fraction numerator 16 sigma cross times 1 plus 12 sigma cross times 5 over denominator 16 sigma plus 12 sigma end fraction equals fraction numerator 19 over denominator 7 end fraction

equals 2.7 blank m f r o m O

The distance of the centre of mass of the $T$ -shaped plate from $O$ is

physics-General

Co-ordinate of CM is given by

X subscript C M end subscript equals fraction numerator m subscript 1 end subscript x subscript 1 end subscript plus m subscript 2 end subscript x subscript 2 end subscript over denominator m subscript 1 end subscript plus m subscript 2 end subscript end fraction

A

B

as two bodies of same system

m subscript 1 end subscript equals l cross times b cross times sigma equals 8 cross times 2 cross times sigma equals 16 sigma

m subscript 2 end subscript equals l cross times b cross times sigma equals 6 cross times 2 cross times sigma equals 12 sigma

O

x subscript 1 end subscript equals 1 blank m comma blank x subscript 2 end subscript equals 2 plus 3 equals 5 blank m

therefore X subscript C M end subscript equals fraction numerator 16 sigma cross times 1 plus 12 sigma cross times 5 over denominator 16 sigma plus 12 sigma end fraction equals fraction numerator 19 over denominator 7 end fraction

equals 2.7 blank m f r o m O

Look at the drawing given in the figure, which has been drawn with ink of uniform line-thickness. The mass of ink used to draw each of the two inner circles, and each of the two line segments is $m$ . The mass of ink used to draw the outer circle is 6 $m$ . The coordinates of the centres of the different parts are : outer circle (0, 0) left inner circle (- $a comma blank a$ ), right inner circle ( $a comma blank a$ ) vertical line (0, 0) and horizontal line (0, - $a$ ). The $y$ - coordinate of the centre of mass of the ink in the drawing is

y subscript C M end subscript equals blank fraction numerator m subscript 1 end subscript y subscript 1 end subscript plus m subscript 2 end subscript y subscript 2 end subscript plus m subscript 3 end subscript y subscript 3 end subscript plus m subscript 4 end subscript y subscript 4 end subscript plus m subscript 5 end subscript y subscript 5 end subscript over denominator m subscript 1 end subscript plus m subscript 2 end subscript plus m subscript 3 end subscript plus m subscript 4 end subscript plus m subscript 5 end subscript end fraction

equals fraction numerator open parentheses 6 m close parentheses open parentheses 0 close parentheses plus m open parentheses a close parentheses plus m open parentheses a close parentheses plus m open parentheses 0 close parentheses plus m left parenthesis negative a right parenthesis over denominator 6 m plus m plus m plus m plus m end fraction equals fraction numerator a over denominator 10 end fraction

Look at the drawing given in the figure, which has been drawn with ink of uniform line-thickness. The mass of ink used to draw each of the two inner circles, and each of the two line segments is $m$ . The mass of ink used to draw the outer circle is 6 $m$ . The coordinates of the centres of the different parts are : outer circle (0, 0) left inner circle (- $a comma blank a$ ), right inner circle ( $a comma blank a$ ) vertical line (0, 0) and horizontal line (0, - $a$ ). The $y$ - coordinate of the centre of mass of the ink in the drawing is

physics-General

y subscript C M end subscript equals blank fraction numerator m subscript 1 end subscript y subscript 1 end subscript plus m subscript 2 end subscript y subscript 2 end subscript plus m subscript 3 end subscript y subscript 3 end subscript plus m subscript 4 end subscript y subscript 4 end subscript plus m subscript 5 end subscript y subscript 5 end subscript over denominator m subscript 1 end subscript plus m subscript 2 end subscript plus m subscript 3 end subscript plus m subscript 4 end subscript plus m subscript 5 end subscript end fraction

equals fraction numerator open parentheses 6 m close parentheses open parentheses 0 close parentheses plus m open parentheses a close parentheses plus m open parentheses a close parentheses plus m open parentheses 0 close parentheses plus m left parenthesis negative a right parenthesis over denominator 6 m plus m plus m plus m plus m end fraction equals fraction numerator a over denominator 10 end fraction

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The molarity of 0.04NBa(OH)2 as a base is-

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