Chemistry-

General

Easy

Question

# Which of the following arrangements does not represent the correct order of the property stated against it?

- Sc < Ti < Cr < Mn : number of oxidation states
- V
^{2+} < Cr^{2+} < Mn^{2+} < Fe^{2+} : paramagnetic behaviour
- Ni
^{2+} < Co^{2+} < Fe^{2+} < Mn^{2+} : lonic size
- Co
^{3+ }< Fe^{3+} < Cr^{3+} < Sc^{3+} : stability in aqueous solution

^{2+}< Cr^{2+}< Mn^{2+}< Fe^{2+}: paramagnetic behaviour^{2+}< Co^{2+}< Fe^{2+}< Mn^{2+}: lonic size^{3+ }< Fe^{3+}< Cr^{3+}< Sc^{3+}: stability in aqueous solution## The correct answer is: V^{2+} < Cr^{2+} < Mn^{2+} < Fe^{2+} : paramagnetic behaviour

### The unpaired electrons in Fe^{2+} ion (four) are less than in Mn^{2+} ion (five)

\Fe^{2+} ion is less paramagnetic than Mn^{2+} ion.

The correct order is :

V^{2+} < Cr^{2+} < Fe^{2+ }< Mn^{2+}

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