Chemistry-
General
Easy
Question
Which of the following pairs is correctly matched
- Isotopes
- Isotones
- Isobars
- Isoelectronic N–3,O–2,Cr+3
The correct answer is: Isotones
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Electronic configuration:1s2,2s22p6,3s23p6 3d54s1represents
Electronic configuration:1s2,2s22p6,3s23p6 3d54s1represents
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Correct statement is:
Correct statement is:
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Which of the following are isoelectronic NO3,CO3 ,ClO3,SO3:
Which of the following are isoelectronic NO3,CO3 ,ClO3,SO3:
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The de-Broglie wavelength of a tennis ball of mass 60g moving with a velocity of 10metres per second is approximately:
The de-Broglie wavelength of a tennis ball of mass 60g moving with a velocity of 10metres per second is approximately:
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Wavelength of some radiation is500nm.What is it wave number
Wavelength of some radiation is500nm.What is it wave number
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In Bohr atomic model radius of Ist orbit of Hydrogenis0.053nmthenradiusof 3rdorbitof Li+2 is:
In Bohr atomic model radius of Ist orbit of Hydrogenis0.053nmthenradiusof 3rdorbitof Li+2 is:
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Which of the following pair is not isoelectronic:
Which of the following pair is not isoelectronic:
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What is the de-Broglies wavelength associated with the hydrogen electron in its third orbit:
What is the de-Broglies wavelength associated with the hydrogen electron in its third orbit:
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The configuration 1s2,2s2,2p5,3s1 shows:
The configuration 1s2,2s2,2p5,3s1 shows:
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The emission spectrum of hydrogen is found to satisfy the expression for the energy change.ΔE(in joules) such that ΔE=2.18× 10–18 
Where n1=1,2,3.....and n2=2,3,4 ......The spectral lines that correspond to Paschan series have:
The emission spectrum of hydrogen is found to satisfy the expression for the energy change.ΔE(in joules) such that ΔE=2.18× 10–18
Where n1=1,2,3.....and n2=2,3,4 ......The spectral lines that correspond to Paschan series have:
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Pair of isoelectronic species is:
Pair of isoelectronic species is:
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The charge of an electron is–1.6×10–19C. The value of free charge on Li+ ion will be–
The charge of an electron is–1.6×10–19C. The value of free charge on Li+ ion will be–
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An element have atomic weight 40 and its electronic configuration is1s2,2s2,2p6,3s2,3p6. Then its atomic number and number of neutrons will be-
An element have atomic weight 40 and its electronic configuration is1s2,2s2,2p6,3s2,3p6. Then its atomic number and number of neutrons will be-
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Which one pair of atoms or ions will have same configuration.
Which one pair of atoms or ions will have same configuration.
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The electronic configuration of an element is1s2, 2s2,2p6,3s2,3p6,3d54s1. This represents its:
The electronic configuration of an element is1s2, 2s2,2p6,3s2,3p6,3d54s1. This represents its:
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