Turito Academy

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Interstitial compounds are chemically inert, so, choice (2) is incorrect

Which of the following statements about the interstitial compounds is incorrect?

Solution for the question - which of the following statements about the interstitial compounds isincorrect? they have higher melting points than the pure metal

Which of the following statements about the interstitial compou-Turito

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Potential energy of a satellite having mass m and rotating at a height of 6.4<img src="data:image/png;base64,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" class="Wirisformula" alt="cross times 10 to the power of 6" width="45" height="17" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mo»§#215;«/mo»«msup»«mn»10«/mn»«mn»6«/mn»«/msup»«/math»'/> m from the surface of earth

Solution for the question - potential energy of a satellite having mass m and rotating at a height of6.4 xx10^(6) m from the surface of earth 4mgre-2mgre

Potential energy of a satellite having mass m and rotating at a-Turito

The slant height of a cone is fixed as  7 cm. If the rate of increase in its height is 0.3 cm/sec. Then the rate of increase in volume when the height is 4cm

Solution for the question - the slant height of a cone is fixed as 7 cm. if the rate of increase inits height is 0.3 cm/sec. then the rate of increase in volume

The slant height of a cone is fixed as 7 cm. if the rate of i-Turito

A satellite with K.E. EK is revolving round the earth in a circular orbit. How much more K.E. should be given to it so that it may just escape into outer space?

Solution for the question - a satellite with k.e. ek is revolving round the earth in a circular orbit.how much more k.e. should be given to it so that it may ju

A satellite with k.e. ek is revolving round the earth in a circ-Turito

If A,B,C are the maximum velocities of the particles moving according to the law <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAASgAAAAjCAYAAAAnt5duAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAXQ/cXWQAABHlJREFUeNrtnU9IFVEUxoeHiIQEESERIYSISAshJEQkBBERCQkk5NFCAoloEW0iIqRF+wgJRCJCQhCJiJA2ERISQURIixBctHDhpoVEPER4nZPn4TjeeV6f986cm98PzsJxnDlzvjnn/n3PKAJAP61kD8i+IRQAAG3MkI2TlREKAIBWUKAAAChQAACAAgUAQIECAAAUKAACTSy2zWh7qbwfIcmtQEEL5AeoQhvZT4RBRQ8KWiA/QIIC2S+EQUWBghbIDxDjJNkk2RhCkXuBghYB5kcd2UOyNbIS2WeyAU/OdJLNkW3Ivd6QXUqcc5zsqfjBNiXH8hgfm6yW61w74N9p0yTPOYpaYx+iFjYf79GeH2XXmvALOSzdrAapZHMeHmpc7tUaC3SR7GPivPdkl2M/D8mxJC1kSwpa7f384Od8JM9vizZNfMbaJSFrwdh8vEdDfqQxQjbtUpNestkMHG8n+2L5gE8Mxx+TjSaOXSF7qaBA2fpRsryeNk18x9oloWph+/5pyQ8TTdKwNbjUpJhSfV0zZQigifnIvNzYK7+rMJHoUt7NqUDZ+tFzgGKgTRPfsXZFyFrYvn9a8iOtp9nhWpOzZH+ky3rawdgzLbA/LK/PM/n1huN8bD1xbE663nn3oNL8qMSDW4Z3ZM2W19Omie9YuyRULWzfPy35keRGtD135kWTDmklfstNCh4eoCTzHK9E8E2pmMXEeVtVrrFpSLBmjwWK78cTxwtkd8gaqyS6az80aeI71i4JVQvbAqUlP+LwPXiyvs63JqPyoi5VScbDBPwr2aA8CIvcTbZCdtNSgPgYtSC++m7R2NcL8mJyoNsSv7f1I2RNsoh1uUb7X7RwUaDyyA9mUYaYJpxrwoGfqdJdq/WBuCdyJqV1Wov9vJ7ShW1IdGEvSmCypN9wzyz8yFuTPGJdCyFrYVugtOXHiIwwMtWE9yQ8c3zNhSpd43jXlCf6BlKKw3yiNXuRQxKUDK1qFn7kqUlesa6lhxOqFrYFSlN+FGRU0ZG1JtxCDDm+Jg8ZrhqOt8n4tQIvSU4bznse7V5x4mXVWxknwHmy1cSxrPzIU5M8Yl0LIWthW6A05cewRe/oUH7wbtR7sXkV3jA1kajErqiXh7ke7Uymcfdvmawvce4HsttyHv/dfUMgJj23Yjxx3CWtREFarVV5QVz5MSsv4rByTXzH2hUha2FboLTkRyVmYx41+dcjmJFhC3fpP8nL6otTUv15NWRLgtpjOO+EPBT7xRNsU9HeScl2mScpp4zJXYytV8RPXtrlpdJOw3mH8cOUFBo18R1rV4SuRaUw7TdnpSE/mHXxxZcmQAGcGIMIwy66pZeyEe18V1ARWgCQLTy5+D1K3z9yVFmU+ZTGWCu8FNnteocWADiCl/ibEAYreKPfMrQAAGilhBAAADTSFYXxdS8AgCMG75LmfVndCAUAQBO8jP06wn/8AAAo45wUpxaEAgCgCd69zRtIjyEUAABN8HI/79zHniQAgDreRnu/dwsAAFTg6l9+gUD5C8ZiDkuZjnWQAAABhXRFWHRNYXRoTUwAPG1hdGggeG1sbnM9Imh0dHA6Ly93d3cudzMub3JnLzE5OTgvTWF0aC9NYXRoTUwiPjxtaT5TPC9taT48bW8+PTwvbW8+PG1uPjYwPC9tbj48bWk+dDwvbWk+PG1vPi08L21vPjxtbj41PC9tbj48bXN1cD48bWk+dDwvbWk+PG1uPjM8L21uPjwvbXN1cD48bW8+LDwvbW8+PG1pPlM8L21pPjxtbz49PC9tbz48bW4+NjwvbW4+PG1pPnQ8L21pPjxtbz4tPC9tbz48bWZyYWM+PG1uPjE8L21uPjxtbj4yPC9tbj48L21mcmFjPjxtc3VwPjxtaT50PC9taT48bW4+MzwvbW4+PC9tc3VwPjxtbz4sPC9tbz48bWk+UzwvbWk+PG1vPj08L21vPjxtbj4xMDwvbW4+PG1pPnQ8L21pPjxtbz4tPC9tbz48bW4+NzwvbW4+PG1zdXA+PG1pPnQ8L21pPjxtbj4zPC9tbj48L21zdXA+PC9tYXRoPqR+Kv0AAAAASUVORK5CYII=" class="Wirisformula" alt="S equals 60 t minus 5 t to the power of 3 end exponent comma S equals 6 t minus fraction numerator 1 over denominator 2 end fraction t to the power of 3 end exponent comma S equals 10 t minus 7 t to the power of 3 end exponent" width="296" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»S«/mi»«mo»=«/mo»«mn»60«/mn»«mi»t«/mi»«mo»-«/mo»«mn»5«/mn»«msup»«mrow»«mi»t«/mi»«/mrow»«mrow»«mn»3«/mn»«/mrow»«/msup»«mo»,«/mo»«mi»S«/mi»«mo»=«/mo»«mn»6«/mn»«mi»t«/mi»«mo»-«/mo»«mfrac»«mrow»«mn»1«/mn»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/mfrac»«msup»«mrow»«mi»t«/mi»«/mrow»«mrow»«mn»3«/mn»«/mrow»«/msup»«mo»,«/mo»«mi»S«/mi»«mo»=«/mo»«mn»10«/mn»«mi»t«/mi»«mo»-«/mo»«mn»7«/mn»«msup»«mrow»«mi»t«/mi»«/mrow»«mrow»«mn»3«/mn»«/mrow»«/msup»«/math»'/> respectively then the ascending order of A,B,C is

Solution for the question - if a,b,c are the maximum velocities of the particles moving according tothe law 5=60 t-5t^(3),5=6t-(1)/(2)t^(3),5=10 t-7t^(3) respec

If a,b,c are the maximum velocities of the particles moving acc-Turito

A satellite moves around the earth in a circular orbit of radius r with speed v, If mass of the satellite is M, its total energy is

Solution for the question - a satellite moves around the earth in a circular orbit of radius r withspeed v, if mass of the satellite is m, its total energy is mv2

A satellite moves around the earth in a circular orbit of radiu-Turito

Which one of the following d-block elements has half-filled penultimate d-subshell as well as half filled penultimate d-subshell as well as half filled valence s-subshell?

Solution for the question - which one of the following d-block elements has half-filled penultimated-subshell as well as half filled penultimate d-subshell as w

Which one of the following d-block elements has half-filled pen-Turito

A conical vessel of height 10ft and semivertical angle <img src="data:image/png;base64,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" class="Wirisformula" alt="30 to the power of ring operator end exponent" width="32" height="16" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«msup»«mrow»«mn»30«/mn»«/mrow»«mrow»«mo»∘«/mo»«/mrow»«/msup»«/math»'/> is full of water. If empties in such away that the height at the water in the vessel is decreasing at a constant rate of 1ft/min. Then the rate at which the volume of water in the vessel is decreasing when its height is  6ft. is

Solution for the question - a conical vessel of height 10ftand semivertical angle 30^(@) is full ofwater. if empties in such away that the height at the water i

A conical vessel of height 10ftand semivertical angle 30^(@) -Turito

If the gravitational force between two objects were proportional to <img src="data:image/png;base64,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" class="Wirisformula" alt="1 over R" width="19" height="35" style="vertical-align:-12px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mn»1«/mn»«mi»R«/mi»«/mfrac»«/math»'/> (and not as <img src="data:image/png;base64,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" class="Wirisformula" alt="1 over R squared" width="27" height="38" style="vertical-align:-15px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨»«mfrac»«mn»1«/mn»«msup»«mi»R«/mi»«mn»2«/mn»«/msup»«/mfrac»«/math»'/>  )where R is separation between them, then a particle in circular orbit under such a force would have, its orbital speed v proportional to

Solution for the question - if the gravitational force between two objects were proportional to (1)/(8)(and not as (1)/(r^(2)) )where r is separation between th

If the gravitational force between two objects were proportiona-Turito

The surface area of a sphere increases at the rate of 1 sq. ft per second, then the rate of increase of volume when the radius is <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABcAAAAQCAYAAAD9L+QYAAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAANvpXuIwAAARdJREFUeNpjYCAfMAGxODEKHYF4GxB/A+IfQHwLiCcAsTAO9R5A/A6KrwAxCz7D9wNxEBCzIYkZAPEOLGpBBj2FyoOAFpRWAeKjpHj9ExYxkCOW4xBfSqzBSkB8A4t4PRCXYxH7j4TLcRkKiqREaLh7ocmtQzMkEkluFRAH4DL0PxouwKEO5BtZHOLyhIJDEOqCk0BsjyX5fcORLL+REpk8UAuQgTk0ZTFgET9Iakb5gcYHhfF8LOpA4gtJMVgPGqnIYBIQp2FRC8pwObgMAnkpFJpBmKA59j4Qx2NJLV5Y9E8B4rm4DLcF4i3QYPgBDVcfLOpA2Z0Di7gWNNf+R8vlRANRIH7OQAMwAZqOO2hhuDG07CAJAAAJ1jyHRe2sswAAAF10RVh0TWF0aE1MADxtYXRoIHhtbG5zPSJodHRwOi8vd3d3LnczLm9yZy8xOTk4L01hdGgvTWF0aE1MIj48bW4+MzwvbW4+PG1pPmY8L21pPjxtaT50PC9taT48L21hdGg+L9NjhwAAAABJRU5ErkJggg==" class="Wirisformula" alt="3 f t" width="23" height="16" style="vertical-align:-3px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mn»3«/mn»«mi»f«/mi»«mi»t«/mi»«/math»'/> is

Solution for the question - the surface area of a sphere increases at the rate of 1 sq. ft per second,then the rate of increase of volume when the radius is 3ft

The surface area of a sphere increases at the rate of 1 sq. ft -Turito

If <img src="data:image/png;base64,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" class="Wirisformula" alt="f open parentheses x close parentheses equals open curly brackets table row cell fraction numerator x minus 1 over denominator 2 x to the power of 2 end exponent minus 7 x plus 5 end fraction comma blank f o r x not equal to 1 end cell row cell negative fraction numerator 1 over denominator 3 end fraction comma blank f o r x equals 1 end cell end table close" width="238" height="95" style="vertical-align:-42px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»f«/mi»«mfenced separators=¨|¨»«mrow»«mi»x«/mi»«/mrow»«/mfenced»«mo»=«/mo»«mfenced open=¨{¨ close=¨¨ separators=¨|¨»«mrow»«mtable»«mtr»«mtd»«mrow»«maligngroup/»«mfrac»«mrow»«mi»x«/mi»«mo»-«/mo»«mn»1«/mn»«/mrow»«mrow»«mn»2«/mn»«msup»«mrow»«mi»x«/mi»«/mrow»«mrow»«mn»2«/mn»«/mrow»«/msup»«mo»-«/mo»«mn»7«/mn»«mi»x«/mi»«mo»+«/mo»«mn»5«/mn»«/mrow»«/mfrac»«mo»,«/mo»«mi» «/mi»«mi»f«/mi»«mi»o«/mi»«mi»r«/mi»«mi»x«/mi»«mo»≠«/mo»«mn»1«/mn»«/mrow»«/mtd»«/mtr»«mtr»«mtd»«mrow»«maligngroup/»«mo»-«/mo»«mfrac»«mrow»«mn»1«/mn»«/mrow»«mrow»«mn»3«/mn»«/mrow»«/mfrac»«mo»,«/mo»«mi» «/mi»«mi»f«/mi»«mi»o«/mi»«mi»r«/mi»«mi»x«/mi»«mo»=«/mo»«mn»1«/mn»«/mrow»«/mtd»«/mtr»«/mtable»«/mrow»«/mfenced»«/math»'/>, then <img src="data:image/png;base64,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" class="Wirisformula" alt="f to the power of ´ end exponent left parenthesis 1 right parenthesis" width="36" height="19" style="vertical-align:-3px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«msup»«mrow»«mi»f«/mi»«/mrow»«mrow»«mi»´«/mi»«/mrow»«/msup»«mo»(«/mo»«mn»1«/mn»«mo»)«/mo»«/math»'/> is equal to

Solution for the question - if f(x)={[(x-1)/(2x^(2)-7x+5)","" for "x!=1],[-(1)/(3)","" for "x=1]:} ,then f(1) is equal to (1)/(3)   -(1)/(3)   -(2)/(9)

If f(x)={[(x-1)/(2x^(2)-7x+5)","" for "x!=1],[-(1)/(3)","" for -Turito

The unpaired electrons in Fe2+ ion (four) are less than in Mn2+ ion (five) \Fe2+ ion is less paramagnetic than Mn2+ ion. The correct order is : V2+ &lt; Cr2+ &lt; Fe2+ &lt; Mn2+

Which of the following arrangements does not represent the correct order of the property stated against it?

Solution for the question - which of the following arrangements does not represent the correct order ofthe property stated against it? co3+ < fe3+ < cr3+ < sc3+ : stability in aqueous solution

Which of the following arrangements does not represent the corr-Turito

Magnetic moment of Cr (Z = 24), Mn+ (Z = 25) and Fe2+ (Z = 26) are a,b,c. They are in the order:

Solution for the question - magnetic moment of cr (z = 24), mn+ (z = 25) and fe2+ (z = 26) are a,b,c.they are in the order: a = b = c

Magnetic moment of cr (z = 24), mn+ (z = 25) and fe2+ (z = 26) -Turito

A geo-stationary satellite is orbiting the earth of a height of  above the surface of earth, R. being the radius of earth. The time period of another satellite at a height of 2.5R  from the surface fo earth is  hr

Solution for the question - a geo-stationary satellite is orbiting the earth of a height of above thesurface of earth, r. being the radius of earth. the time pe

A geo-stationary satellite is orbiting the earth of a height of-Turito

A point <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAsAAAANCAYAAAB/9ZQ7AAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAMyZLetQAAAIVJREFUeNpjYMAEP4D4PxR/AeJVQOyIRR2DChBfQOKzAbELEN8HYi10xQFAvBSLIclAXIIuWI9NEAg6gDgHXRDkPj80MVEgvgXEwuiKQYKSSHxjID6KzYNMQPwHGgrvoIqa0TTDgTkQ72cgEkQC8XxiFU8C4jRiFa8DYi9iFYM8xcFALQAAM/sYFg8AKnAAAABJdEVYdE1hdGhNTAA8bWF0aCB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMTk5OC9NYXRoL01hdGhNTCI+PG1pPlA8L21pPjwvbWF0aD4oc3y9AAAAAElFTkSuQmCC" class="Wirisformula" alt="P" width="11" height="13" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»P«/mi»«/math»'/> is moving with uniform velocity <img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAkAAAAKCAYAAABmBXS+AAAACXBIWXMAAA7EAAAOxAGVKw4bAAAABGJhU0UAAAAJufgqOgAAAGpJREFUeNpjYICAICBeyoAJ9gKxF4yjAsQX0BTYA/FJdF3fgJgJiX8ciF3QFYEE9aBsDyA+iMV6hoVAHAplg6y2xKYoC4i7gDgAiHcz4AAgX6wD4itAbIBLERcQ/wDiTQwEwAcg1mEgBwAA5+gQxmAj9O8AAABJdEVYdE1hdGhNTAA8bWF0aCB4bWxucz0iaHR0cDovL3d3dy53My5vcmcvMTk5OC9NYXRoL01hdGhNTCI+PG1pPnY8L21pPjwvbWF0aD476OiVAAAAAElFTkSuQmCC" class="Wirisformula" alt="v" width="9" height="10" style="vertical-align:-1px" role="math" data-mathml='«math xmlns=¨http://www.w3.org/1998/Math/MathML¨ »«mi»v«/mi»«/math»'/> along a line AB.'O'  is a point on the line perpendicular drawn to AB at A and at a distance ' l' from it. The angular velocity of P  about 'O' is

Solution for the question - a point p is moving with uniform velocity along a line ab.'o' is a pointon the line perpendicular drawn to abat aand at a distance '

A point p is moving with uniform velocity along a line ab.'o'-Turito

The distance of a geo-stationary satellite from the center of the earth (Radius R=6400 km ) is nearest to

Solution for the question - the distance of a geo-stationary satellite from the center of the earth(radius r=6400 km ) is nearest to 18r10r7r