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Maths-

General

Easy

Question

Convert $5 5 over 6$ into improper fraction :

$\frac{52}{3}$
$\frac{35}{6}$
$\frac{24}{6}$
$\frac{62}{5}$

The correct answer is: $35 over 6$

$5 5 over 6$ = $fraction numerator left parenthesis space 6 space cross times space 5 space plus space 5 space right parenthesis over denominator 6 end fraction$ = $fraction numerator left parenthesis 30 plus 5 right parenthesis over denominator 6 end fraction$ = $35 over 6$

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The correct statement about the following disaccharide is:
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II)

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II)

Chemistry-General

A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S.
$table row cell P fraction numerator 1. M e M g B r over denominator 2. H to the power of plus end exponent comma H subscript 2 end subscript O end fraction Q fraction numerator 1. O subscript 3 end subscript over denominator 2. Z n comma H subscript 2 end subscript O end fraction R fraction numerator 1. O H to the power of minus end exponent over denominator 2. capital delta end fraction S end cell row cell 3. H subscript 2 end subscript S O subscript 4 end subscript comma capital delta end cell end table$
The structures of the products Q and R, respectively, are:

A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S.
$table row cell P fraction numerator 1. M e M g B r over denominator 2. H to the power of plus end exponent comma H subscript 2 end subscript O end fraction Q fraction numerator 1. O subscript 3 end subscript over denominator 2. Z n comma H subscript 2 end subscript O end fraction R fraction numerator 1. O H to the power of minus end exponent over denominator 2. capital delta end fraction S end cell row cell 3. H subscript 2 end subscript S O subscript 4 end subscript comma capital delta end cell end table$
The structures of the products Q and R, respectively, are:

Chemistry-General

Consider the following reactions I and II,
I)
II)
Products 'X' and 'Y' are respectively:

Consider the following reactions I and II,
I)
II)
Products 'X' and 'Y' are respectively:

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In which of the following cases, the nitration will take place at meta-position?
I)
II)
III)
IV)

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II)
III)
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Chemistry-General

The correct order of decreasing basicity of the following compounds is:
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Phenol . gives two polymers on condensation with formaldehyde:

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