General
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Maths-

cos squared space open parentheses 60 to the power of ring operator plus x close parentheses minus cos squared space open parentheses 60 to the power of ring operator minus x close parentheses element of open square brackets negative m over 2 comma m over 2 close square brackets not stretchy rightwards double arrow straight m equals

Maths-General

  1. 3
  2. 1
  3. negative square root of 3
  4. square root of 3

    Answer:The correct answer is: square root of 3

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    Related Questions to study

    General
    maths-

    The value of integer n for which the function f left parenthesis x right parenthesis equals fraction numerator sin begin display style space end style x x over denominator sin begin display style space end style left parenthesis x divided by n right parenthesis end fraction has 4 pi as its period is

    The value of integer n for which the function f left parenthesis x right parenthesis equals fraction numerator sin begin display style space end style x x over denominator sin begin display style space end style left parenthesis x divided by n right parenthesis end fraction has 4 pi as its period is

    maths-General
    General
    maths-

    cos squared space open parentheses 60 to the power of ring operator minus x close parentheses plus cos squared space open parentheses 60 to the power of ring operator plus x close parentheses element of

    cos squared space open parentheses 60 to the power of ring operator minus x close parentheses plus cos squared space open parentheses 60 to the power of ring operator plus x close parentheses element of

    maths-General
    General
    physics-

    A body is travelling in a straight line with a uniformly increasing speed. Which one of the plot represents the changes in distance (s) travelled with time (t)

    s equals u t plus fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent
    s equals fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent [because u equals 0]
    It is an equation of parabola

    A body is travelling in a straight line with a uniformly increasing speed. Which one of the plot represents the changes in distance (s) travelled with time (t)

    physics-General
    s equals u t plus fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent
    s equals fraction numerator 1 over denominator 2 end fraction a t to the power of 2 end exponent [because u equals 0]
    It is an equation of parabola
    General
    physics-

    The effective capacitance between points X and Y shown in figure. Assuming C subscript 2 end subscript equals 10 blank muF and that outer capacitors are all 4 blank muF is

    The arrangement shows a Wheatstone bridge.
    As fraction numerator C subscript 1 end subscript over denominator C subscript 3 end subscript end fraction equals fraction numerator C subscript 4 end subscript over denominator C subscript 5 end subscript end fraction equals 1 comma blanktherefore the bridge is balanced.
    fraction numerator 1 over denominator C subscript s subscript 1 end subscript end subscript end fraction equals fraction numerator 1 over denominator 4 end fraction plus fraction numerator 1 over denominator 4 end fraction equals fraction numerator 2 over denominator 4 end fraction equals fraction numerator 1 over denominator 2 end fraction comma C subscript s subscript 1 end subscript end subscript equals 2 mu blank F
    Similarly, C subscript s end subscript subscript 2 end subscript equals 2 mu blank F
    therefore effective capacitance
    equals C subscript p end subscript equals C subscript s end subscript subscript 1 end subscript plus C subscript s end subscript subscript 2 end subscript equals 2 plus 2 plus equals 4 mu blank F

    The effective capacitance between points X and Y shown in figure. Assuming C subscript 2 end subscript equals 10 blank muF and that outer capacitors are all 4 blank muF is

    physics-General
    The arrangement shows a Wheatstone bridge.
    As fraction numerator C subscript 1 end subscript over denominator C subscript 3 end subscript end fraction equals fraction numerator C subscript 4 end subscript over denominator C subscript 5 end subscript end fraction equals 1 comma blanktherefore the bridge is balanced.
    fraction numerator 1 over denominator C subscript s subscript 1 end subscript end subscript end fraction equals fraction numerator 1 over denominator 4 end fraction plus fraction numerator 1 over denominator 4 end fraction equals fraction numerator 2 over denominator 4 end fraction equals fraction numerator 1 over denominator 2 end fraction comma C subscript s subscript 1 end subscript end subscript equals 2 mu blank F
    Similarly, C subscript s end subscript subscript 2 end subscript equals 2 mu blank F
    therefore effective capacitance
    equals C subscript p end subscript equals C subscript s end subscript subscript 1 end subscript plus C subscript s end subscript subscript 2 end subscript equals 2 plus 2 plus equals 4 mu blank F
    General
    physics-

    The four capacitors, each of 25 muF are connected as shown in figure. The DC voltmeter reads 200 V. the change on each plate of capacitor is

    Charge on each plate of each capacitor
    Q equals plus-or-minus C V equals plus-or-minus 25 cross times 10 to the power of negative 6 end exponent cross times 200
    equals plus-or-minus 5 cross times 10 to the power of negative 3 end exponent C

    The four capacitors, each of 25 muF are connected as shown in figure. The DC voltmeter reads 200 V. the change on each plate of capacitor is

    physics-General
    Charge on each plate of each capacitor
    Q equals plus-or-minus C V equals plus-or-minus 25 cross times 10 to the power of negative 6 end exponent cross times 200
    equals plus-or-minus 5 cross times 10 to the power of negative 3 end exponent C
    General
    physics-

    For the circuit shown in figure the charge on 4muF capacitor is

    Combined capacity of 1 blank mu F and 5 mu F blank= 1 + 5=6 blank mu F
    Now, 4 mu F blankand 6 mu F are in series.
    therefore blank fraction numerator 1 over denominator C subscript s end subscript end fraction equals fraction numerator 1 over denominator 4 end fraction plus fraction numerator 1 over denominator 6 end fraction plus fraction numerator 3 plus 2 over denominator 12 end fraction equals fraction numerator 5 over denominator 12 end fraction
    C subscript s end subscript equals fraction numerator 12 over denominator 5 end fraction mu F
    Charge in the arm containing 4 mu F blankcapacitor is
    q equals C subscript s end subscript cross times V equals fraction numerator 12 over denominator 5 end fraction cross times 10 equals 24 blank mu C

    For the circuit shown in figure the charge on 4muF capacitor is

    physics-General
    Combined capacity of 1 blank mu F and 5 mu F blank= 1 + 5=6 blank mu F
    Now, 4 mu F blankand 6 mu F are in series.
    therefore blank fraction numerator 1 over denominator C subscript s end subscript end fraction equals fraction numerator 1 over denominator 4 end fraction plus fraction numerator 1 over denominator 6 end fraction plus fraction numerator 3 plus 2 over denominator 12 end fraction equals fraction numerator 5 over denominator 12 end fraction
    C subscript s end subscript equals fraction numerator 12 over denominator 5 end fraction mu F
    Charge in the arm containing 4 mu F blankcapacitor is
    q equals C subscript s end subscript cross times V equals fraction numerator 12 over denominator 5 end fraction cross times 10 equals 24 blank mu C
    General
    chemistry-

    i) 

    ii) 

    iii) 

    iv)  Me minus identical to negative straight H rightwards arrow with text  dil.H  end text subscript 2 SO subscript 4 plus Hg to the power of 2 plus end exponent on top

    Which of the statements are correct?

    i) 

    ii) 

    iii) 

    iv)  Me minus identical to negative straight H rightwards arrow with text  dil.H  end text subscript 2 SO subscript 4 plus Hg to the power of 2 plus end exponent on top

    Which of the statements are correct?

    chemistry-General
    General
    physics-

    A particle is moving with uniform acceleration along a straight line. The average velocity of the particle from P to Q is 8 m s to the power of negative 1 end exponent and that from Q to Sis 12 m s to the power of negative 1 end exponent. If Q S minus P Q, then the average velocity from P to S is

    Average velocity equals fraction numerator 2 cross times 8 cross times 12 over denominator 8 plus 12 end fraction m s to the power of negative 1 end exponent equals 9.6 m s to the power of negative 1 end exponent

    A particle is moving with uniform acceleration along a straight line. The average velocity of the particle from P to Q is 8 m s to the power of negative 1 end exponent and that from Q to Sis 12 m s to the power of negative 1 end exponent. If Q S minus P Q, then the average velocity from P to S is

    physics-General
    Average velocity equals fraction numerator 2 cross times 8 cross times 12 over denominator 8 plus 12 end fraction m s to the power of negative 1 end exponent equals 9.6 m s to the power of negative 1 end exponent
    General
    physics-

    A body begins to walk eastward along a street in front of his house and the graph of his position from home is shown in the following figure. His average speed for the whole time interval is equal to

    Average speed is the ratio of distance to time taken
    Distance travelled from 0 to 5 s equals 40 blank m
    Distance travelled from 5 to 10 s equals 0 blank m
    Distance travelled from 10 to 15 s equals 60 blank m
    Distance travelled from 15to 20 s equals 20
    So, total distance equals 40 plus 0 plus 60 plus 20 equals 120 blank m
    Total time taken equals 20 blank m i n u t e s
    Hence, average speed
    equals fraction numerator d i s t a n c e blank t r a v e l l e d blank left parenthesis m right parenthesis over denominator t i m e blank left parenthesis m i n right parenthesis end fraction equals fraction numerator 120 over denominator 20 end fraction equals 6 blank m divided by m i n

    A body begins to walk eastward along a street in front of his house and the graph of his position from home is shown in the following figure. His average speed for the whole time interval is equal to

    physics-General
    Average speed is the ratio of distance to time taken
    Distance travelled from 0 to 5 s equals 40 blank m
    Distance travelled from 5 to 10 s equals 0 blank m
    Distance travelled from 10 to 15 s equals 60 blank m
    Distance travelled from 15to 20 s equals 20
    So, total distance equals 40 plus 0 plus 60 plus 20 equals 120 blank m
    Total time taken equals 20 blank m i n u t e s
    Hence, average speed
    equals fraction numerator d i s t a n c e blank t r a v e l l e d blank left parenthesis m right parenthesis over denominator t i m e blank left parenthesis m i n right parenthesis end fraction equals fraction numerator 120 over denominator 20 end fraction equals 6 blank m divided by m i n
    General
    physics-

    Which of the following options is correct for the object having a straight line motion represented by the following graph

    From given figure, it is clear that the net displacement is zero. So average velocity will be zero

    Which of the following options is correct for the object having a straight line motion represented by the following graph

    physics-General
    From given figure, it is clear that the net displacement is zero. So average velocity will be zero
    General
    maths-

    Let f left parenthesis x right parenthesis equals cos space square root of p x where p equals left square bracket a right square bracket where  is the integral part of x. If the period of f(x) is pi, then a element of

    Let f left parenthesis x right parenthesis equals cos space square root of p x where p equals left square bracket a right square bracket where  is the integral part of x. If the period of f(x) is pi, then a element of

    maths-General
    General
    maths-

    If the period of fraction numerator cos space left parenthesis sin space left parenthesis n x right parenthesis right parenthesis over denominator tan space left parenthesis x divided by n right parenthesis end fraction comma n element of N is 6 pi then n=

    If the period of fraction numerator cos space left parenthesis sin space left parenthesis n x right parenthesis right parenthesis over denominator tan space left parenthesis x divided by n right parenthesis end fraction comma n element of N is 6 pi then n=

    maths-General
    General
    maths-

    The minimum and maximum values of sin to the power of 4 x plus cos to the power of 4 space x are

    The minimum and maximum values of sin to the power of 4 x plus cos to the power of 4 space x are

    maths-General
    General
    maths-

    In straight triangle A B C comma sum a left parenthesis sin space B minus sin space C right parenthesis equals

    In straight triangle A B C comma sum a left parenthesis sin space B minus sin space C right parenthesis equals

    maths-General
    General
    physics-

    Figure shows a network of eight resistors, each equal to 2blank capital omega, connected to a 3V battery of negligible internal resistance. The current I in the circuit is

    Figure shows a network of eight resistors, each equal to 2blank capital omega, connected to a 3V battery of negligible internal resistance. The current I in the circuit is

    physics-General