Maths-

General

Easy

Question

# Digit at unit place of sum (1!)^{2} +(2!)^{2} +(3!)^{2} ……… +(2008!)^{2} is

- 5
- 7
- 9
- None

## The correct answer is: 7

### S = 1 + 4 + 36 + 576 + …….. +(2008!)^{2}= 617 + all other terms will have 0 at unit place

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