Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Physics

General

Easy

Question

Escape velocity of a body of 1 kg. on a planet is 100ms^-1 . Gravitational potential energy of the body at the planet is =.....j

-5000
-1000
-2400
5000

The correct answer is: -5000

Related Questions to study

What is the intensity of gravitational field at the center of spherical shell

What is the intensity of gravitational field at the center of spherical shell

A rocket is launched with velocity 10 $k m s to the power of negative 1 end exponent$ . If radius of earth is R then maximum height attained by it will be =…….

A rocket is launched with velocity 10 $k m s to the power of negative 1 end exponent$ . If radius of earth is R then maximum height attained by it will be =…….

The masses and radius of earth and moon are M₁ ,R₁and M₂ R₂respectively. Their centres are d distance of apart. The minimum velocity with which a particle of mass should be projected from a point mid way between their centres so that it escapes to infinity is……

The masses and radius of earth and moon are M₁ ,R₁and M₂ R₂respectively. Their centres are d distance of apart. The minimum velocity with which a particle of mass should be projected from a point mid way between their centres so that it escapes to infinity is……

parallel

If P= $fraction numerator A to the power of 2 end exponent B over denominator C to the power of 3 end exponent end fraction$ where percentage error in $A comma B$ and $C$ are respectively $plus 2 percent sign plus-or-minus 3 percent sign$ and $plus-or-minus 5 percent sign$ then total percentage error in measurement of $p$

If P= $fraction numerator A to the power of 2 end exponent B over denominator C to the power of 3 end exponent end fraction$ where percentage error in $A comma B$ and $C$ are respectively $plus 2 percent sign plus-or-minus 3 percent sign$ and $plus-or-minus 5 percent sign$ then total percentage error in measurement of $p$

physics-General

The mass of the earth is 6.00 $cross times 10 to the power of 24$ Kg and that of the moon is 7.40 $cross times 10 to the power of 22$ kg. The constant of gravitation G=6.667 $cross times 10 negative 11 to the power of blank$ Nm^-2 kg^--2.The potential energy of the system is -7.79 $cross times 10 to the power of 28$ Joules. the mean distance between the earth and moon is =

The mass of the earth is 6.00 $cross times 10 to the power of 24$ Kg and that of the moon is 7.40 $cross times 10 to the power of 22$ kg. The constant of gravitation G=6.667 $cross times 10 negative 11 to the power of blank$ Nm^-2 kg^--2.The potential energy of the system is -7.79 $cross times 10 to the power of 28$ Joules. the mean distance between the earth and moon is =

$text If end text a with not stretchy bar on top equals ı with not stretchy bar on top plus 2 ȷ with not stretchy bar on top plus 3 k with not stretchy bar on top comma b with not stretchy bar on top equals negative ı with not stretchy bar on top plus 2 ȷ with not stretchy bar on top plus k with not stretchy bar on top comma c with not stretchy bar on top equals 3 ı with not stretchy bar on top plus ȷ with not stretchy bar on top text and end text a with not stretchy bar on top plus t b with not stretchy bar on top$ is perpendicular to $stack c with ‾ on top$ , then $t equals$

For this question, we should know the rules of dot product.

$text If end text a with not stretchy bar on top equals ı with not stretchy bar on top plus 2 ȷ with not stretchy bar on top plus 3 k with not stretchy bar on top comma b with not stretchy bar on top equals negative ı with not stretchy bar on top plus 2 ȷ with not stretchy bar on top plus k with not stretchy bar on top comma c with not stretchy bar on top equals 3 ı with not stretchy bar on top plus ȷ with not stretchy bar on top text and end text a with not stretchy bar on top plus t b with not stretchy bar on top$ is perpendicular to $stack c with ‾ on top$ , then $t equals$

For this question, we should know the rules of dot product.

parallel

The acute angle made by the line joining the points $left parenthesis 1 comma negative 3 , 2 right parenthesis$ and $left parenthesis 3 comma negative 5 , 1 right parenthesis$ with the $Y$ -axis is

We should remember the formula of direction cosines of all the angles.

The acute angle made by the line joining the points $left parenthesis 1 comma negative 3 , 2 right parenthesis$ and $left parenthesis 3 comma negative 5 , 1 right parenthesis$ with the $Y$ -axis is

We should remember the formula of direction cosines of all the angles.

If $a with bar on top equals negative ı with bar on top plus ȷ with bar on top plus 2 k with bar on top comma b with bar on top equals 2 l with bar on top plus ȷ with bar on top minus k with bar on top comma c with bar on top equals negative 2 l with bar on top plus ȷ with bar on top plus 3 k with bar on top$ then the angle between $2 a with not stretchy bar on top minus c with not stretchy bar on top$ and is

If $a with bar on top equals negative ı with bar on top plus ȷ with bar on top plus 2 k with bar on top comma b with bar on top equals 2 l with bar on top plus ȷ with bar on top minus k with bar on top comma c with bar on top equals negative 2 l with bar on top plus ȷ with bar on top plus 3 k with bar on top$ then the angle between $2 a with not stretchy bar on top minus c with not stretchy bar on top$ and is

In a gravitational field, at a point where the gravitational potential is zero

In a gravitational field, at a point where the gravitational potential is zero

parallel

A spherical planet has a mass MP and diameter Dip A particle of mass falling freely near the surface of this planet will experience an acceleration due to gravity, equal to

A spherical planet has a mass MP and diameter Dip A particle of mass falling freely near the surface of this planet will experience an acceleration due to gravity, equal to

The height at which the weight of a body becomes 1/16 th its weight on the surface of (radius R) is

The height at which the weight of a body becomes 1/16 th its weight on the surface of (radius R) is

The acceleration of a body due to the attraction of the earth (radius R ) at a distance 2R from the surface of the earth is (g = acceleration due to gravity at the surface of earth)

The acceleration of a body due to the attraction of the earth (radius R ) at a distance 2R from the surface of the earth is (g = acceleration due to gravity at the surface of earth)

parallel

Acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth, If the ratio of densities of earth $rho subscript theta$ and moon $rho subscript m$ is $rho subscript t over rho subscript equals equals 5 divided by 3$ then radius of moon Rm in terns of Re will be,

Acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth, If the ratio of densities of earth $rho subscript theta$ and moon $rho subscript m$ is $rho subscript t over rho subscript equals equals 5 divided by 3$ then radius of moon Rm in terns of Re will be,

A research satellite of mass 200 kg. circles the earth in an orbit of average radius 3R/2 where R is radius of earth. Assuming the gravitational pall 10N, the pull on the satellite will be...N

A research satellite of mass 200 kg. circles the earth in an orbit of average radius 3R/2 where R is radius of earth. Assuming the gravitational pall 10N, the pull on the satellite will be...N

If the value of ' g ' acceleration due to gravity, at earth surface fs .10ms^-2 its value in ms^-2 at the center of earth, which is assumed to be a sphere of Radius ' R ' meter and uniform density is

If the value of ' g ' acceleration due to gravity, at earth surface fs .10ms^-2 its value in ms^-2 at the center of earth, which is assumed to be a sphere of Radius ' R ' meter and uniform density is

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.