Question
Explain how you can use your graphing calculator to show that the rational expressions 
and
are equivalent under a given domain. What is true about the graph
at x = 0and Why?
Hint:
Multiplying top and bottom of the expression by the same number or value will result in equivalent expression.
We are asked to explain why the given expressions are equivalent, what is true about the graph at x = 0 and explain.
The correct answer is: The graph at x = 0, will have a value y =7.
Step 1 of 2:
Simplify the expression
Once we simplified it, we got it reduced as.
Hence, they are equivalent.
Step 2 of 2:
The domains of both the expressions are set of real numbers.
Considering the expression , it is clear that it’s a polynomial. Hence, the domain would be set of real numbers.
For the expression, we could simplify the expression to 
which again is a polynomial.
The graph at x = 0, will have a value y=7.
The domain of any polynomial is set of real numbers.
Related Questions to study
If 
then find the quotient from the following four option, when A is divided by B.
If then find the quotient from the following four option, when A is divided by B.
Find the extraneous solution of 
Find the extraneous solution of
Explain why the process of dividing by a rational number is the same as multiplying by its reciprocal.
Explain why the process of dividing by a rational number is the same as multiplying by its reciprocal.
Sketch the graph of y = 2x - 5.
Sketch the graph of y = 2x - 5.
Simplify each expressions and state the domain : 
Simplify each expressions and state the domain :
Reduce the following rational expressions to their lowest terms
Reduce the following rational expressions to their lowest terms
Describe the error student made in multiplying and simplifying
Describe the error student made in multiplying and simplifying
The LCM of the polynomials 
is.
The LCM of the polynomials is.
Write the equation in slope-intercept form of the line that passes through the points (5, 4) and (-1, 6).
The slope intercept form is y = mx + b, where m represents the slope and b represents the y-intercept. We can draw the graph of a linear equation on the x-y coordinate plane using this form of a linear equation.
Steps for determining a line's equation from two points:
Step 1: The slope formula used to calculate the slope.
Step 2: To determine the y-intercept, use the slope and one of the points (b).
Step 3: Once you know the values for m and b, we can plug them into the slope-intercept form of a line, i.e., (y = mx + b), to obtain the line's equation.
Write the equation in slope-intercept form of the line that passes through the points (5, 4) and (-1, 6).
The slope intercept form is y = mx + b, where m represents the slope and b represents the y-intercept. We can draw the graph of a linear equation on the x-y coordinate plane using this form of a linear equation.
Steps for determining a line's equation from two points:
Step 1: The slope formula used to calculate the slope.
Step 2: To determine the y-intercept, use the slope and one of the points (b).
Step 3: Once you know the values for m and b, we can plug them into the slope-intercept form of a line, i.e., (y = mx + b), to obtain the line's equation.
=1 why is a valid identity under the domain of all real numbers except 
.
is:
