Maths-

General

Easy

Question

# Find the area of a verandah 2.25 m wide constructed outside a room 5.5 m long and 4 m wide.

## The correct answer is: Final Answer:- ∴ Area of the given verandah is 63 m2.

### Hint:-

Area of a rectangle = length ×breadth

Step-by-step solution:-

From the adjacent diagram,

Let the outer rectangle represent the verandah around the room.

∴ Length of the outer rectangle = length of the room + 2 (width of the verandah)

∴ Length of the outer rectangle = 5.5 + 2 (2.25)

∴ Length of the outer rectangle = 5.5 + 4.5

∴ Length of the outer rectangle = 10 m ........................................................... (Equation i)

Also, breadth of the outer rectangle = breadth of the room + 2 (width of the verandah)

∴ breadth of the outer rectangle = 4 + 2 (2.25)

∴ breadth of the outer rectangle = 4 + 4.5

∴ breadth of the outer rectangle = 8.5 m .................................................. (Equation ii)

Area of the outer rectangle = length × breadth

Final Answer:-

∴ Area of the given verandah is 63 m2.

∴ Area of the outer rectangle = 10 × 8.5 ......................................................... (From Equations i & ii)

∴ Area of the outer rectangle = 85 m2 ............................................................ (Equation iii)

Area of the room = length × breadth

∴ Area of the room = 5.5 × 4 ......................................................................... (From given information)

∴ Area of the room = 22 m2 .......................................................................... (Equation iv)

Now, Area of the verandah = Area of outer rectangle - Area of the inner room

∴ Area of the verandah = 85 - 22 ............................................................ (From Equations iii & iv)

∴ Area of the verandah = 63 m2

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