Maths-

General

Easy

### Question

#### Find the area of the triangle whose base and height are 16cm and 8cm.

- 54 sq cm
- 62 sq cm
- 64 sq cm
- 55 sq cm

#### The correct answer is: 64 sq cm

#### Area of triangle = × b × h

= × 16 × 8

= 64 sq. cm

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### Related Questions to study

Maths-

#### What is prime factorization of 28

2x2x7

#### What is prime factorization of 28

Maths-General

2x2x7

Maths-

#### convert 17 into roman numerals.

17=10+7

=X + VII

=XVII

=X + VII

=XVII

#### convert 17 into roman numerals.

Maths-General

17=10+7

=X + VII

=XVII

=X + VII

=XVII

Maths-

#### GCF of 28 and 54

Factors of 28 = 1,2,7,14,28

Factors of 54 = 1,2,3,6,9,27,54

Greatest common factor = 2

Factors of 54 = 1,2,3,6,9,27,54

Greatest common factor = 2

#### GCF of 28 and 54

Maths-General

Factors of 28 = 1,2,7,14,28

Factors of 54 = 1,2,3,6,9,27,54

Greatest common factor = 2

Factors of 54 = 1,2,3,6,9,27,54

Greatest common factor = 2

Maths-

#### Find the range of the following data: 2,8,3,9,1,0

Range = highest value – smallest value = 9-0 =9

#### Find the range of the following data: 2,8,3,9,1,0

Maths-General

Range = highest value – smallest value = 9-0 =9

Maths-

#### What is the lowest term of 24/40

24 and 40 both are divisible by 8

24 /8

40/8

{24/8 = 3 and 40/8 = 5}

Lowest term =3/5

24 /8

40/8

{24/8 = 3 and 40/8 = 5}

Lowest term =3/5

#### What is the lowest term of 24/40

Maths-General

24 and 40 both are divisible by 8

24 /8

40/8

{24/8 = 3 and 40/8 = 5}

Lowest term =3/5

24 /8

40/8

{24/8 = 3 and 40/8 = 5}

Lowest term =3/5

Maths-

#### ¼ litre of milk cost Rs 15/2 . Find the cost of 9/2 litre of milk.

Cost of ¼ litre milk= Rs 15/2

Cost of 1 litre milk =Rs (15/2) /(1/4)

=Rs (15/2 *4/1)

= Rs 30

Cost of 9/2 litre of milk =30 * 9/2

= (30*9)/2

= Rs 135

Cost of 1 litre milk =Rs (15/2) /(1/4)

=Rs (15/2 *4/1)

= Rs 30

Cost of 9/2 litre of milk =30 * 9/2

= (30*9)/2

= Rs 135

#### ¼ litre of milk cost Rs 15/2 . Find the cost of 9/2 litre of milk.

Maths-General

Cost of ¼ litre milk= Rs 15/2

Cost of 1 litre milk =Rs (15/2) /(1/4)

=Rs (15/2 *4/1)

= Rs 30

Cost of 9/2 litre of milk =30 * 9/2

= (30*9)/2

= Rs 135

Cost of 1 litre milk =Rs (15/2) /(1/4)

=Rs (15/2 *4/1)

= Rs 30

Cost of 9/2 litre of milk =30 * 9/2

= (30*9)/2

= Rs 135

Maths-

#### -3/-8 is

Positive rational number

#### -3/-8 is

Maths-General

Positive rational number

Maths-

#### If all the sides of triangle ,so the triangle is called __________ triangle:

If all the sides of a triangle is equal, then its called an equilateral

Triangle.

Triangle.

#### If all the sides of triangle ,so the triangle is called __________ triangle:

Maths-General

If all the sides of a triangle is equal, then its called an equilateral

Triangle.

Triangle.

Maths-

#### Least common multiple for 12 and 5 is

As 12 and 5 are co-prime, there product will be the LCM

#### Least common multiple for 12 and 5 is

Maths-General

As 12 and 5 are co-prime, there product will be the LCM

Maths-

#### What is LCM of 4 and 6.

LCM of 4 & 6= 2*2*3 = 12

#### What is LCM of 4 and 6.

Maths-General

LCM of 4 & 6= 2*2*3 = 12

Maths-

#### The area of a rectangular park is 1500 sq m. If the lenth is 50m, find its width. Also find the perimeter of the park.

Area of rectangular park = 1500 sq m

Length = 50m

Bredth of the park= (1500/50)

= 30m

Perimeter =2*(l+b)

= 2*(50 + 30)

=2* 80

= 160m

Length = 50m

Bredth of the park= (1500/50)

= 30m

Perimeter =2*(l+b)

= 2*(50 + 30)

=2* 80

= 160m

#### The area of a rectangular park is 1500 sq m. If the lenth is 50m, find its width. Also find the perimeter of the park.

Maths-General

Area of rectangular park = 1500 sq m

Length = 50m

Bredth of the park= (1500/50)

= 30m

Perimeter =2*(l+b)

= 2*(50 + 30)

=2* 80

= 160m

Length = 50m

Bredth of the park= (1500/50)

= 30m

Perimeter =2*(l+b)

= 2*(50 + 30)

=2* 80

= 160m

Maths-

#### 11 divided by 1/3

11 ÷1/3 = 11 x 3/1 = 33

#### 11 divided by 1/3

Maths-General

11 ÷1/3 = 11 x 3/1 = 33

Maths-

#### Himani saves Rs 700 a month and pratibha saves Rs 900 a month. Find the ratio in their savings.

Himani’s ratio = Rs 700 per month

Pratibha’s ratio = Rs 900 per month

Ratio of their savings = 700/900

= (700/100) / (900/100)

=7/9

= 7:9

Pratibha’s ratio = Rs 900 per month

Ratio of their savings = 700/900

= (700/100) / (900/100)

=7/9

= 7:9

#### Himani saves Rs 700 a month and pratibha saves Rs 900 a month. Find the ratio in their savings.

Maths-General

Himani’s ratio = Rs 700 per month

Pratibha’s ratio = Rs 900 per month

Ratio of their savings = 700/900

= (700/100) / (900/100)

=7/9

= 7:9

Pratibha’s ratio = Rs 900 per month

Ratio of their savings = 700/900

= (700/100) / (900/100)

=7/9

= 7:9

Maths-

#### What is 8 in roman numeral

V= 5 adding 3 times I will be 8

#### What is 8 in roman numeral

Maths-General

V= 5 adding 3 times I will be 8

Maths-

#### Find the area of a given triangle whose perimeter is equal to 26cm .10 cm

Perimeter= 26cm

Height=10cm

Hypotenuse=12cm

Area=?

Perimeter of triangle=sum of sides

26=10+12+ b

26=22+b

26-22=b

4cm=b

Area=1/2*base*height

=1\2 * 4*10= 20 sq. cm

Height=10cm

Hypotenuse=12cm

Area=?

Perimeter of triangle=sum of sides

26=10+12+ b

26=22+b

26-22=b

4cm=b

Area=1/2*base*height

=1\2 * 4*10= 20 sq. cm

#### Find the area of a given triangle whose perimeter is equal to 26cm .10 cm

Maths-General

Perimeter= 26cm

Height=10cm

Hypotenuse=12cm

Area=?

Perimeter of triangle=sum of sides

26=10+12+ b

26=22+b

26-22=b

4cm=b

Area=1/2*base*height

=1\2 * 4*10= 20 sq. cm

Height=10cm

Hypotenuse=12cm

Area=?

Perimeter of triangle=sum of sides

26=10+12+ b

26=22+b

26-22=b

4cm=b

Area=1/2*base*height

=1\2 * 4*10= 20 sq. cm