Maths-

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### Question

#### Find the Lateral surface area of a triangular prism if, three sides are 12cm, 10cm, 8cm and height is 20cm:

- 700 sq cm
- 500 sq cm
- 600 sq cm
- 800 sq cm

#### The correct answer is: 600 sq cm

#### LSA of triangular prism = (a+b+c)h

=(12+10+8)*20

=30*20

=600 sq cm

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### Related Questions to study

Maths-

#### Find surface area of a rectangular prism, if its dimensions are 22cm, 10cm, 12cm:

Surface area of a rectangular prism = 2(lb+bh+hl)

=2(22*10+ 10*12+22*12)

=2(220 + 120 + 264)

=2(604)

=1208 sq cm

=2(22*10+ 10*12+22*12)

=2(220 + 120 + 264)

=2(604)

=1208 sq cm

#### Find surface area of a rectangular prism, if its dimensions are 22cm, 10cm, 12cm:

Maths-General

Surface area of a rectangular prism = 2(lb+bh+hl)

=2(22*10+ 10*12+22*12)

=2(220 + 120 + 264)

=2(604)

=1208 sq cm

=2(22*10+ 10*12+22*12)

=2(220 + 120 + 264)

=2(604)

=1208 sq cm

Maths-

#### Find the value of x:

60

x+60=180 {linear angle sum property}

x= 180-60

x = 120

x= 180-60

x = 120

#### Find the value of x:

60

Maths-General

x+60=180 {linear angle sum property}

x= 180-60

x = 120

x= 180-60

x = 120

Maths-

#### At 5:00 PM the temperature was -2 degrees Celsius. At 10:00 PM the temperature was 2 degrees Celsius. When was it colder?

5:00 PM

#### At 5:00 PM the temperature was -2 degrees Celsius. At 10:00 PM the temperature was 2 degrees Celsius. When was it colder?

Maths-General

5:00 PM

Maths-

#### Greatest common factor of 9 and 18:

Factors of 9: 1, 3, 9

Factors of 18: 1,2,3,6,9,18

Greatest common factor is 9

Factors of 18: 1,2,3,6,9,18

Greatest common factor is 9

#### Greatest common factor of 9 and 18:

Maths-General

Factors of 9: 1, 3, 9

Factors of 18: 1,2,3,6,9,18

Greatest common factor is 9

Factors of 18: 1,2,3,6,9,18

Greatest common factor is 9

Maths-

#### Find the distance between these the points A and B

A(6,6) B(10,12)

d= ((x

d=((10-6)

_{2}– x_{1})^{2 }+ (y_{2}– y_{1})^{2})^{1/2}d=((10-6)

^{2}+(12-6)^{2})^{1/2}^{ }d= ((4)^{2 }+ (6)^{2})^{1/2}^{ }d=(16 + 36)^{1/2}^{ }d=(100)^{1/2}^{ }d=10cm#### Find the distance between these the points A and B

A(6,6) B(10,12)

Maths-General

d= ((x

d=((10-6)

_{2}– x_{1})^{2 }+ (y_{2}– y_{1})^{2})^{1/2}d=((10-6)

^{2}+(12-6)^{2})^{1/2}^{ }d= ((4)^{2 }+ (6)^{2})^{1/2}^{ }d=(16 + 36)^{1/2}^{ }d=(100)^{1/2}^{ }d=10cmMaths-

#### The smallest no. that is multiple of each of two or more no. is called:

least common multiple

#### The smallest no. that is multiple of each of two or more no. is called:

Maths-General

least common multiple

Maths-

#### If the LCM of 12 and 15 is 60, find the GCF

LCM * GCF = a * b

60 * GCF = 12 *15

GCF = (12*15)/60

GCF= 3

60 * GCF = 12 *15

GCF = (12*15)/60

GCF= 3

#### If the LCM of 12 and 15 is 60, find the GCF

Maths-General

LCM * GCF = a * b

60 * GCF = 12 *15

GCF = (12*15)/60

GCF= 3

60 * GCF = 12 *15

GCF = (12*15)/60

GCF= 3

Maths-

#### Round off 4783 to nearest hundred

As the digit at hundreds place is 7, which is greater than 5 therefore it is rounded off to higher number

#### Round off 4783 to nearest hundred

Maths-General

As the digit at hundreds place is 7, which is greater than 5 therefore it is rounded off to higher number

Maths-

#### Choose the pair of equivalent ratios:

12:22 = 12/22, dividing numerator and denominator by 2,it will be 6/11= 6:11

#### Choose the pair of equivalent ratios:

Maths-General

12:22 = 12/22, dividing numerator and denominator by 2,it will be 6/11= 6:11

Maths-

#### Represent 11/6 as decimal and percent

11/6 = 11x100 /6 % = 1100/6 = 183.33%

11/6 = 1.83

11/6 = 1.83

#### Represent 11/6 as decimal and percent

Maths-General

11/6 = 11x100 /6 % = 1100/6 = 183.33%

11/6 = 1.83

11/6 = 1.83

Maths-

#### The product of two no. 12/3 . If one number is 6. Find the other no,

lets assume second no = a

a * 6=12/3

a= 12 /(6*3)

a= 2/3

a * 6=12/3

a= 12 /(6*3)

a= 2/3

#### The product of two no. 12/3 . If one number is 6. Find the other no,

Maths-General

lets assume second no = a

a * 6=12/3

a= 12 /(6*3)

a= 2/3

a * 6=12/3

a= 12 /(6*3)

a= 2/3

Maths-

#### Which of the following is an equivalent ratio to 2:7

2:7 = 2/7 , multiplying numerator and denominator by 4, we get 2x4 / 7x4 = 8/28

#### Which of the following is an equivalent ratio to 2:7

Maths-General

2:7 = 2/7 , multiplying numerator and denominator by 4, we get 2x4 / 7x4 = 8/28

Maths-

#### what is the least common multiples of 6 and 9:

Multiples of 6 : 6, 12, 18, 24

Multiples of 9: 9,18,27,36

Least common multiple is 18

Multiples of 9: 9,18,27,36

Least common multiple is 18

#### what is the least common multiples of 6 and 9:

Maths-General

Multiples of 6 : 6, 12, 18, 24

Multiples of 9: 9,18,27,36

Least common multiple is 18

Multiples of 9: 9,18,27,36

Least common multiple is 18

Maths-

#### Two angles are supplementary and one exceeds the other by 10 degree. Find the angles.

Let the measure of one angle be x then other angle is x+10.

As the angles are supplementary

X+ (x+10)=180

2x + 10= 180

2x = 170

X = 170/2

X = 85

Hence, the angles are 85 and 95.

As the angles are supplementary

X+ (x+10)=180

2x + 10= 180

2x = 170

X = 170/2

X = 85

Hence, the angles are 85 and 95.

#### Two angles are supplementary and one exceeds the other by 10 degree. Find the angles.

Maths-General

Let the measure of one angle be x then other angle is x+10.

As the angles are supplementary

X+ (x+10)=180

2x + 10= 180

2x = 170

X = 170/2

X = 85

Hence, the angles are 85 and 95.

As the angles are supplementary

X+ (x+10)=180

2x + 10= 180

2x = 170

X = 170/2

X = 85

Hence, the angles are 85 and 95.

Maths-

#### Find the range of the following data:

6, 5, 3 ,7 ,2 ,8 ,9 2, 13, 4

Range = difference between the highest and the lowest value = 13 -2 =11

#### Find the range of the following data:

6, 5, 3 ,7 ,2 ,8 ,9 2, 13, 4

Maths-General

Range = difference between the highest and the lowest value = 13 -2 =11