Maths-
General
Easy
Question
Find the side of cube whose surface area is 294 sq cm:
- 6cm
- 7cm
- 8cm
- 9cm
The correct answer is: 7cm
let the side of the cube be x cm
surface area of cube =6x2
294 = 6x2
294/6 =x2
(49)1/2 = x
7cm =x
Related Questions to study
Maths-
what are the greatest common factors of 6 and 8:
Factors of 6: 1, 2, 3, 6
Factors of 8: 1,2, 4,8
Common factors are 1 and 2.
Greatest common factor: 2
Factors of 8: 1,2, 4,8
Common factors are 1 and 2.
Greatest common factor: 2
what are the greatest common factors of 6 and 8:
Maths-General
Factors of 6: 1, 2, 3, 6
Factors of 8: 1,2, 4,8
Common factors are 1 and 2.
Greatest common factor: 2
Factors of 8: 1,2, 4,8
Common factors are 1 and 2.
Greatest common factor: 2
Maths-
What is 25 percent of 1000
25 percent of 1000 = (25/ 100) x 1000 = 250
What is 25 percent of 1000
Maths-General
25 percent of 1000 = (25/ 100) x 1000 = 250
Maths-
Which of the following ratio is equivalent to 8:2
8 and 2 both are divisible by 2
(8/2)/(2/2)
4/1
4:1
(8/2)/(2/2)
4/1
4:1
Which of the following ratio is equivalent to 8:2
Maths-General
8 and 2 both are divisible by 2
(8/2)/(2/2)
4/1
4:1
(8/2)/(2/2)
4/1
4:1
Maths-
The surface area of a cuboid is 3600 sq m. If its dimensions are in the ratio 4:2:2, find its volume.
let the dimensions of the cuboid be 4x,2x,2x.
surface area of cuboid
=2[4x*2x + 2x*2x + 2x*4x]
=2[8x2 + 4x2 + 8x2]
=2[20x2]
=40x2
According to the question,
40x2=3600
X2 =3600/40
X2=9
X=(9)1/2
X=3
Dimensions =12m , 6m , 6m
Volume= 12*6*6
Volume= 432 cu m
surface area of cuboid
=2[4x*2x + 2x*2x + 2x*4x]
=2[8x2 + 4x2 + 8x2]
=2[20x2]
=40x2
According to the question,
40x2=3600
X2 =3600/40
X2=9
X=(9)1/2
X=3
Dimensions =12m , 6m , 6m
Volume= 12*6*6
Volume= 432 cu m
The surface area of a cuboid is 3600 sq m. If its dimensions are in the ratio 4:2:2, find its volume.
Maths-General
let the dimensions of the cuboid be 4x,2x,2x.
surface area of cuboid
=2[4x*2x + 2x*2x + 2x*4x]
=2[8x2 + 4x2 + 8x2]
=2[20x2]
=40x2
According to the question,
40x2=3600
X2 =3600/40
X2=9
X=(9)1/2
X=3
Dimensions =12m , 6m , 6m
Volume= 12*6*6
Volume= 432 cu m
surface area of cuboid
=2[4x*2x + 2x*2x + 2x*4x]
=2[8x2 + 4x2 + 8x2]
=2[20x2]
=40x2
According to the question,
40x2=3600
X2 =3600/40
X2=9
X=(9)1/2
X=3
Dimensions =12m , 6m , 6m
Volume= 12*6*6
Volume= 432 cu m
Maths-
which multiplication property states that,”The mode of grouping the factors does not change the result of the multiplication”.
associative property i.e.,
(a*b)*c =a*(b*c)
(a*b)*c =a*(b*c)
which multiplication property states that,”The mode of grouping the factors does not change the result of the multiplication”.
Maths-General
associative property i.e.,
(a*b)*c =a*(b*c)
(a*b)*c =a*(b*c)
Maths-
4 divided by 16/11
4 ÷ 16/11 = 4 x 11/16 = 11/4
4 divided by 16/11
Maths-General
4 ÷ 16/11 = 4 x 11/16 = 11/4
Maths-
Divide 56 by 3:
Q=18, R=2
Divide 56 by 3:
Maths-General
Q=18, R=2
Maths-
What is the mean of first five whole numbers
Mean = (0+1+2+3+4) / 5 = 2
What is the mean of first five whole numbers
Maths-General
Mean = (0+1+2+3+4) / 5 = 2
Maths-
what is the opposite integer of 4:
opposite integer of 4 is -4
what is the opposite integer of 4:
Maths-General
opposite integer of 4 is -4
Maths-
What is the place value of 3 in 234,569
Ten-thousands
What is the place value of 3 in 234,569
Maths-General
Ten-thousands
Maths-
In a school, there are 1000 students. Out of these, 700 students are girls. Find the percentage of boys and girls in the school.
Percentage of girls=(700/1000)*100
=70%
No. of boys= 1000-700=300
Percentage of boys= (300/1000)*100
=30%
=70%
No. of boys= 1000-700=300
Percentage of boys= (300/1000)*100
=30%
In a school, there are 1000 students. Out of these, 700 students are girls. Find the percentage of boys and girls in the school.
Maths-General
Percentage of girls=(700/1000)*100
=70%
No. of boys= 1000-700=300
Percentage of boys= (300/1000)*100
=30%
=70%
No. of boys= 1000-700=300
Percentage of boys= (300/1000)*100
=30%
Maths-
Find the least common multiple of 9 and 10.
LCM of 9 and 10 = 3*3*2*5= 90
Find the least common multiple of 9 and 10.
Maths-General
LCM of 9 and 10 = 3*3*2*5= 90
Maths-
There are two circle with same centre O. The radius of larger circle is 4cm and that of the smaller circle is 2cm.
Find area of the shaded region.
Ar of shaded region =ar. of larger circle – ar. of smaller circle
{ar. of circle = 22/7*r*r}
= 22/7*4*4-22/7*2*2
=22/7(16-4)
=22/7*12
=37.7 sq cm
{ar. of circle = 22/7*r*r}
= 22/7*4*4-22/7*2*2
=22/7(16-4)
=22/7*12
=37.7 sq cm
There are two circle with same centre O. The radius of larger circle is 4cm and that of the smaller circle is 2cm.
Find area of the shaded region.
Maths-General
Ar of shaded region =ar. of larger circle – ar. of smaller circle
{ar. of circle = 22/7*r*r}
= 22/7*4*4-22/7*2*2
=22/7(16-4)
=22/7*12
=37.7 sq cm
{ar. of circle = 22/7*r*r}
= 22/7*4*4-22/7*2*2
=22/7(16-4)
=22/7*12
=37.7 sq cm
Maths-
Write 5 in roman numbers
The number 5 is represented as V in roman.
Write 5 in roman numbers
Maths-General
The number 5 is represented as V in roman.
Maths-
Is 4/16 is equivalent to
Dividing the numerator and denominator by 4, we get 1/4
Is 4/16 is equivalent to
Maths-General
Dividing the numerator and denominator by 4, we get 1/4
