Maths-
General
Easy

Question

Find the solution of the system of equations.
y equals 0.5 x squared minus 8 x plus 13
y equals x minus 3

hintHint:

A quadratic equation of the form x squared plus open parentheses a plus b close parentheses x plus a b can be simplified into open parentheses x plus a right parenthesis left parenthesis x plus b close parentheses. This can be further solved by equating it to zero.
We are asked to solve the set of equation.

The correct answer is: We are asked to solve the set of equation.


    Step 1 of 3:
    The LHS of the given set is same. Hence, equate the equations.
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell 0.5 x squared minus 8 x plus 13 equals x minus 3 space space space space space space end cell row cell 0.5 x squared minus 8 x minus x plus 13 plus 3 equals 0 end cell row cell 0.5 x squared minus 9 x plus 16 equals 0 space space space space space space space space space space space space end cell row cell 5 x squared minus 90 x plus 160 equals 0 space space space space space space space space space space space end cell row cell x squared minus 18 x plus 32 equals 0 space space space space space space space space space space space space space space end cell end table space
    Here, we multiply the whole equation by ten to remove the decimal. After then, we take out the five to simplify them.
    Step 2 of 3:
    Solve the simplified equation:
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell x squared minus 18 x plus 32 equals 0 space space space space space space space space space space space end cell row cell x squared minus 16 x minus 2 x plus 32 equals 0 space space space end cell row cell x left parenthesis x minus 16 right parenthesis minus 2 left parenthesis x minus 16 right parenthesis equals 0 end cell row cell left parenthesis x minus 2 right parenthesis left parenthesis x minus 16 right parenthesis equals 0 space space space space space space space space space space space end cell row cell left parenthesis x minus 2 right parenthesis equals 0 straight & left parenthesis x minus 16 right parenthesis equals 0 space space end cell row cell x equals 2 straight & x equals 16 space space space space space space space space space space space space space space space space space end cell end table
    Step 3 of 3:
    Substitute the found values of x in any of the equations to get the values of y;
    When x=2,
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell y equals x minus 3 end cell row cell y equals 2 minus 3 end cell row cell y equals negative 1 end cell end table
    When x=16,
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell y equals x minus 3 space space end cell row cell y equals 16 minus 3 end cell row cell y equals 13 space space space space space space end cell end table
    Thus, the required solutions are: (2, -1) and (16, 13)
     

    You can also solve a set of equation by graphing them. The points where the equations intersect all together would be their solutions.

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