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Question

Given: π‘šβˆ π‘ƒ = 30Β°, π‘šβˆ π‘„ = 30Β° , π‘šβˆ π‘„ = π‘šβˆ π‘…
Prove: π‘šβˆ π‘ƒ β‰… π‘šβˆ π‘… = 30Β°

hintHint:

Use Transitive Property

The correct answer is:


    SOL – It is given that π‘šβˆ π‘ƒ = 30Β° and Β π‘šβˆ π‘„ = 30Β°

    rightwards double arrow π‘šβˆ π‘ƒ = π‘šβˆ π‘„Β Β Β Β Β Β Β Β Β Β  ---- (1)
    Further, it is given that π‘šβˆ π‘„ = π‘šβˆ π‘… Β Β Β ---- (1)
    Using transitive property which states that if A = B and B = C then A = C
    We get from (1) and (2),

    π‘šβˆ P = π‘šβˆ R = 30Β°
    Hence Proved

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