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Easy

Question

Given five noncollinear points, make a conjecture about the number of ways to connect different pairs of points.

The correct answer is: 4 + 3 + 2 + 1 = 10


    We have given the 5 non-collinear points
    We have to find the number of ways to connect the different pairs of points
    We will consider figure


    We will consider the points from A to E
    Here we will consider point A
    Point A have 4 options to pair, that are B, C, D, E.
    If we consider point B then,
    Point B have 3 points to pair that are C, D , E. Because we have considered the pair with A before.
    If we consider point C then,
    Point C have 2 points to pair, that are D, E.
    If we consider point D then
    Point D have 1 point to pair, that are E.
    Therefore total number of ways the points can be paired is = 4 + 3 + 2 + 1 = 10

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