Chemistry-
General
Easy

Question

Glycerol on oxidation with bismuth nitrate mainly gives:

  1. Glyceric acid
  2. Tartronic acid
  3. Mesoxalic acid
  4. Oxalic acid

The correct answer is: Mesoxalic acid

Book A Free Demo

+91

Grade*

Related Questions to study

General
chemistry-

Anisole is the product obtained from phenol by the reaction known as

In presence of N a O H space o r space K O H comma space phenol reacts with alkyl halide and gives phenolic ether left parenthesis C subscript 6 H subscript 5 O R right parenthesis. C subscript 6 H subscript 5 O H plus N a O H not stretchy ⟶ for negative H subscript 2 O of C subscript 6 H subscript 5 O minus N a stack not stretchy ⟶ with R X on top with negative N a X below C subscript 6 H subscript 5 minus O minus R Vapours of C subscript 6 H subscript 5 O H space a n d space C H subscript 3 O H comma with red hot T h O subscript 2 (thoria) give anisole (phenolic ether). 

Anisole is the product obtained from phenol by the reaction known as

chemistry-General
In presence of N a O H space o r space K O H comma space phenol reacts with alkyl halide and gives phenolic ether left parenthesis C subscript 6 H subscript 5 O R right parenthesis. C subscript 6 H subscript 5 O H plus N a O H not stretchy ⟶ for negative H subscript 2 O of C subscript 6 H subscript 5 O minus N a stack not stretchy ⟶ with R X on top with negative N a X below C subscript 6 H subscript 5 minus O minus R Vapours of C subscript 6 H subscript 5 O H space a n d space C H subscript 3 O H comma with red hot T h O subscript 2 (thoria) give anisole (phenolic ether). 
General
chemistry-

Propan-2-ol on reacting with C l subscript 2 produces:

Propan-2-ol on reacting with C l subscript 2 produces:

chemistry-General
General
chemistry-

Proof spirit contains about:

The percentage of alcohol is expressed as proof spirit for tax lavy. It contains 57.1 % (by vol.) or 48% (by wt.) of alcohol.

Proof spirit contains about:

chemistry-General
The percentage of alcohol is expressed as proof spirit for tax lavy. It contains 57.1 % (by vol.) or 48% (by wt.) of alcohol.
General
physics-

A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing the object, we again get a real image on the screen which is 16 cm tall. The length of the object must be

O equals square root of I subscript 1 end subscript I subscript 2 end subscript end root equals square root of 4 cross times 16 end root equals 8 c m

A convex lens makes a real image 4 cm long on a screen. When the lens is shifted to a new position without disturbing the object, we again get a real image on the screen which is 16 cm tall. The length of the object must be

physics-General
O equals square root of I subscript 1 end subscript I subscript 2 end subscript end root equals square root of 4 cross times 16 end root equals 8 c m
General
physics-

The slit of a collimator is illuminated by a source as shown in the adjoining figures. The distance between the slit S and the collimating lens L is equal to the focal length of the lens. The correct direction of the emergent beam will be as shown in figure

In case of convex lens if rays are coming from the focus, then the emergent rays after refraction are parallel to principal axis.

The slit of a collimator is illuminated by a source as shown in the adjoining figures. The distance between the slit S and the collimating lens L is equal to the focal length of the lens. The correct direction of the emergent beam will be as shown in figure

physics-General
In case of convex lens if rays are coming from the focus, then the emergent rays after refraction are parallel to principal axis.
General
physics-

Two similar plano-convex lenses are combined together in three different ways as shown in the adjoining figure. The ratio of the focal lengths in three cases will be

In each case two plane-convex lens are placed close to each other, and fraction numerator 1 over denominator F end fraction equals fraction numerator 1 over denominator f subscript 1 end subscript end fraction plus fraction numerator 1 over denominator f subscript 2 end subscript end fraction.

Two similar plano-convex lenses are combined together in three different ways as shown in the adjoining figure. The ratio of the focal lengths in three cases will be

physics-General
In each case two plane-convex lens are placed close to each other, and fraction numerator 1 over denominator F end fraction equals fraction numerator 1 over denominator f subscript 1 end subscript end fraction plus fraction numerator 1 over denominator f subscript 2 end subscript end fraction.
General
physics-

White light is incident on the interface of glass and air as shown in the figure. If green light is just totally internally reflected then the emerging ray in air contains

C equals sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator mu end fraction close parentheses and mu proportional to fraction numerator 1 over denominator lambda end fraction
Yellow, orange and red have higher wavelength than green, so m will be less for these rays, consequently critical angle for these rays will be high, hence if green is just totally internally reflected then yellow, orange and red rays will emerge out.

White light is incident on the interface of glass and air as shown in the figure. If green light is just totally internally reflected then the emerging ray in air contains

physics-General
C equals sin to the power of negative 1 end exponent invisible function application open parentheses fraction numerator 1 over denominator mu end fraction close parentheses and mu proportional to fraction numerator 1 over denominator lambda end fraction
Yellow, orange and red have higher wavelength than green, so m will be less for these rays, consequently critical angle for these rays will be high, hence if green is just totally internally reflected then yellow, orange and red rays will emerge out.
General
physics-

A ray of light is incident at an angle i from denser to rare medium. The reflected and the refracted rays are mutually perpendicular. The angle of reflection and the angle of refraction are respectively r and r’, then the critical angle will be

D mu subscript R end subscript equals fraction numerator sin invisible function application i over denominator sin invisible function application r to the power of ´ end exponent end fraction rightwards double arrow subscript R end subscript rightwards arrow over short leftwards arrow mu subscript D end subscript equals fraction numerator sin invisible function application r to the power of ´ end exponent over denominator sin invisible function application   i end fraction equals fraction numerator 1 over denominator sin invisible function application C end fraction
rightwards double arrow sin invisible function application C equals fraction numerator sin invisible function application i over denominator sin invisible function application left parenthesis 90 minus r right parenthesis end fraction equals fraction numerator sin invisible function application i over denominator cos invisible function application r end fraction equals fraction numerator sin invisible function application i over denominator cos invisible function application i end fraction (as Ði = Ðr)
rightwards double arrow sin invisible function application C equals tan invisible function application i rightwards double arrow C equals sin to the power of negative 1 end exponent invisible function application left parenthesis tan invisible function application i right parenthesis

A ray of light is incident at an angle i from denser to rare medium. The reflected and the refracted rays are mutually perpendicular. The angle of reflection and the angle of refraction are respectively r and r’, then the critical angle will be

physics-General
D mu subscript R end subscript equals fraction numerator sin invisible function application i over denominator sin invisible function application r to the power of ´ end exponent end fraction rightwards double arrow subscript R end subscript rightwards arrow over short leftwards arrow mu subscript D end subscript equals fraction numerator sin invisible function application r to the power of ´ end exponent over denominator sin invisible function application   i end fraction equals fraction numerator 1 over denominator sin invisible function application C end fraction
rightwards double arrow sin invisible function application C equals fraction numerator sin invisible function application i over denominator sin invisible function application left parenthesis 90 minus r right parenthesis end fraction equals fraction numerator sin invisible function application i over denominator cos invisible function application r end fraction equals fraction numerator sin invisible function application i over denominator cos invisible function application i end fraction (as Ði = Ðr)
rightwards double arrow sin invisible function application C equals tan invisible function application i rightwards double arrow C equals sin to the power of negative 1 end exponent invisible function application left parenthesis tan invisible function application i right parenthesis
General
physics-

A fish is a little away below the surface of a lake. If the critical angle is 49 degree, then the fish could see things above the water surface within an angular range of theta to the power of o end exponent where

From figure given in question theta equals 2 c equals 98 degree.

A fish is a little away below the surface of a lake. If the critical angle is 49 degree, then the fish could see things above the water surface within an angular range of theta to the power of o end exponent where

physics-General
From figure given in question theta equals 2 c equals 98 degree.
General
physics-

A ray of light passes through four transparent media with refractive indices mu subscript 1 end subscript. mu subscript 2 end subscript mu subscript 3 end subscript comma text  and end text mu subscript 4 end subscript as shown in the figure. The surfaces of all media are parallel. If the emergent ray CD is parallel to the incident ray AB, we must have

For successive refraction through different media mu sin invisible function application theta equalsconstant. Here as theta is same in the two extreme media, mu subscript 1 end subscript equals mu subscript 4 end subscript.

A ray of light passes through four transparent media with refractive indices mu subscript 1 end subscript. mu subscript 2 end subscript mu subscript 3 end subscript comma text  and end text mu subscript 4 end subscript as shown in the figure. The surfaces of all media are parallel. If the emergent ray CD is parallel to the incident ray AB, we must have

physics-General
For successive refraction through different media mu sin invisible function application theta equalsconstant. Here as theta is same in the two extreme media, mu subscript 1 end subscript equals mu subscript 4 end subscript.
General
chemistry-

The acidic character of 1 degree comma 2 degree comma 3 degree spacealcohols, H subscript 2 O and R C identical to C H is of the order

Alcohols are more acidic than alkynes but less acidic than water thus, the correct order of acidity is H subscript 2 O greater than 1 degree greater than 2 degree greater than 3 degree greater than R C identical to C H

The acidic character of 1 degree comma 2 degree comma 3 degree spacealcohols, H subscript 2 O and R C identical to C H is of the order

chemistry-General
Alcohols are more acidic than alkynes but less acidic than water thus, the correct order of acidity is H subscript 2 O greater than 1 degree greater than 2 degree greater than 3 degree greater than R C identical to C H
General
chemistry-

Ethanol is more soluble in water but ether is less soluble because:


Both shows H-bonding, however the increase in hydrophobic character (due to two alkyl groups in ether), the H-bonding weakens.

Ethanol is more soluble in water but ether is less soluble because:

chemistry-General

Both shows H-bonding, however the increase in hydrophobic character (due to two alkyl groups in ether), the H-bonding weakens.
General
chemistry-

How many structural isomers are known for C subscript 4 H subscript 10 O ?

4 alcohols (butan-1-ol; butan-2-ol; 2-methyl butan-1-ol; 2-methyl butan-2-ol) and 3 ethers (diethyl ether, methyl-propyl ether and methyl isopropyl ether).

How many structural isomers are known for C subscript 4 H subscript 10 O ?

chemistry-General
4 alcohols (butan-1-ol; butan-2-ol; 2-methyl butan-1-ol; 2-methyl butan-2-ol) and 3 ethers (diethyl ether, methyl-propyl ether and methyl isopropyl ether).
General
chemistry-

Methanol and ethanol can be distinguished by the following:

C subscript 2 H subscript 5 O H gives iodoform test.

Methanol and ethanol can be distinguished by the following:

chemistry-General
C subscript 2 H subscript 5 O H gives iodoform test.
General
chemistry-

An alcohol on alk. K M n O subscript 4 oxidation gives first acetone and on further oxidation acetic acid. It is:

C H subscript 3 C H subscript 2 O H not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C H O not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C O O H  (Aldehyde and acid of same carbon atoms)
C H subscript 3 C H O H C H subscript 2 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O C H subscript 3 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O O H plus H C O O H  (Acid of less carbon atom)

An alcohol on alk. K M n O subscript 4 oxidation gives first acetone and on further oxidation acetic acid. It is:

chemistry-General
C H subscript 3 C H subscript 2 O H not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C H O not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C O O H  (Aldehyde and acid of same carbon atoms)
C H subscript 3 C H O H C H subscript 2 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O C H subscript 3 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O O H plus H C O O H  (Acid of less carbon atom)