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Chemistry-

General

Easy

Question

How many structural isomers are known for $C subscript 4 H subscript 10 O ?$

4
3
6
7

The correct answer is: 7

4 alcohols (butan-1-ol; butan-2-ol; 2-methyl butan-1-ol; 2-methyl butan-2-ol) and 3 ethers (diethyl ether, methyl-propyl ether and methyl isopropyl ether).

Related Questions to study

Methanol and ethanol can be distinguished by the following:

C subscript 2 H subscript 5 O H

gives iodoform test.

Methanol and ethanol can be distinguished by the following:

chemistry-General

C subscript 2 H subscript 5 O H

gives iodoform test.

An alcohol on alk. $K M n O subscript 4$ oxidation gives first acetone and on further oxidation acetic acid. It is:

C H subscript 3 C H subscript 2 O H not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C H O not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C O O H

(Aldehyde and acid of same carbon atoms)

C H subscript 3 C H O H C H subscript 2 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O C H subscript 3 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O O H plus H C O O H

(Acid of less carbon atom)

An alcohol on alk. $K M n O subscript 4$ oxidation gives first acetone and on further oxidation acetic acid. It is:

chemistry-General

C H subscript 3 C H subscript 2 O H not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C H O not stretchy rightwards arrow with left square bracket 0 right square bracket on top C H subscript 3 C O O H

(Aldehyde and acid of same carbon atoms)

C H subscript 3 C H O H C H subscript 2 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O C H subscript 3 not stretchy rightwards arrow with left square bracket O right square bracket on top C H subscript 3 C O O H plus H C O O H

(Acid of less carbon atom)

The alcohol that produces turbidity immediately with $Z n C I subscript 2 divided by c o n c. space H C I$ at room temperature

M i x t u r e space o f space a n space h y d r o u s space Z n C l subscript 2 space end subscript a n d space c o n c. H C l

is known as Lucas reagent. Lucas test is used for the distinction between primary, secondary and tertiary alcohols.
The tertiary alcohol reacts immediately with Lucas reagent producing turbidity. The secondary alcohol gives turbidity within 5-10 min and primary alcohol doesn’t give turbidity at all at room temperature. In the given alternates, 2-hydroxy-2-methyl propane is

3 degree space

alcohol, so it is more reactive.

The alcohol that produces turbidity immediately with $Z n C I subscript 2 divided by c o n c. space H C I$ at room temperature

chemistry-General

M i x t u r e space o f space a n space h y d r o u s space Z n C l subscript 2 space end subscript a n d space c o n c. H C l

is known as Lucas reagent. Lucas test is used for the distinction between primary, secondary and tertiary alcohols.
The tertiary alcohol reacts immediately with Lucas reagent producing turbidity. The secondary alcohol gives turbidity within 5-10 min and primary alcohol doesn’t give turbidity at all at room temperature. In the given alternates, 2-hydroxy-2-methyl propane is

3 degree space

alcohol, so it is more reactive.

parallel

The conversion of m-nitrophenol to resorcinol involves respectively

The conversion of m-nitrophenol to resorcinol involves respectively

chemistry-General

At 530 K, glycerol reacts with oxalic acid to produce

Oxalic acid on reaction with glycerol at 530K temperature furnishallyl alcohol.

At 530 K, glycerol reacts with oxalic acid to produce

chemistry-General

Oxalic acid on reaction with glycerol at 530K temperature furnishallyl alcohol.

The following reaction is known as

In the presence of anhydrous

Z n C l subscript 2 comma

phenol form salicyladehyde. It is Gattermann-aldehyde reaction.

The following reaction is known as

chemistry-General

In the presence of anhydrous

Z n C l subscript 2 comma

phenol form salicyladehyde. It is Gattermann-aldehyde reaction.

parallel

On heating glycerol with conc. $H subscript 2 S O subscript 4 comma$ a compound is obtained which has bad odour. The compound is:

On heating glycerol with conc. $H subscript 2 S O subscript 4 comma$ a compound is obtained which has bad odour. The compound is:

chemistry-General

On conversion into the Grignard reagent followed by treatment with absolute ethanol, how many isomeric alkyl chlorides would yield 2-methylbutane?

R H space i s space left parenthesis C H subscript 3 right parenthesis subscript 2 space C H bullet C H subscript 2 space C H subscript 3

On conversion into the Grignard reagent followed by treatment with absolute ethanol, how many isomeric alkyl chlorides would yield 2-methylbutane?

chemistry-General

R H space i s space left parenthesis C H subscript 3 right parenthesis subscript 2 space C H bullet C H subscript 2 space C H subscript 3

What is formed when glycerol reacts with excess of HI?

When glycerol reacts with HI

comma space i s o minus p r o p y l space

iodide is obtained

What is formed when glycerol reacts with excess of HI?

chemistry-General

When glycerol reacts with HI

comma space i s o minus p r o p y l space

iodide is obtained

parallel

General formula for alcohols is:

General formula for alcohols is

C subscript n H subscript left parenthesis 2 n plus 1 right parenthesis O H.

Primary alcohols have

negative C H subscript 2 space O H space g p.

Secondary Alcohols have

and tertiary alcohols have

General formula for alcohols is:

chemistry-General

General formula for alcohols is

C subscript n H subscript left parenthesis 2 n plus 1 right parenthesis O H.

Primary alcohols have

negative C H subscript 2 space O H space g p.

Secondary Alcohols have

and tertiary alcohols have

Which of the following compounds is weakest acid?

Electron withdrawing groups (like

– N O subscript 2 right parenthesis

increase the acidity of phenols by stabilising corresponding phenoxide ion. The effect of

– N O subscript 2

group will beminimum at m-position due to lack of increased delocalisation of electrons in it. Hence, m-nitrophenol is the weakest acid among these.

Which of the following compounds is weakest acid?

chemistry-General

Electron withdrawing groups (like

– N O subscript 2 right parenthesis

increase the acidity of phenols by stabilising corresponding phenoxide ion. The effect of

– N O subscript 2

group will beminimum at m-position due to lack of increased delocalisation of electrons in it. Hence, m-nitrophenol is the weakest acid among these.

Assertion :We cannot produce a real image by plane or convex mirrors under any circumstances
Reason : The focal length of a convex mirror is always taken as positive

Assertion :We cannot produce a real image by plane or convex mirrors under any circumstances
Reason : The focal length of a convex mirror is always taken as positive

physics-General

parallel

An organic compound reacts with $P C l subscript 5$ to give. The compound with sodium metal gives $n minus b u tan e. space T h u s comma space A space a n d space B space a r e colon$

An organic compound reacts with $P C l subscript 5$ to give. The compound with sodium metal gives $n minus b u tan e. space T h u s comma space A space a n d space B space a r e colon$

chemistry-General

If f : R → R is continuous and differentiable function such that $not stretchy integral subscript negative 1 end subscript superscript x end superscript blank$ f(t) dt + f¢¢¢ (3) $not stretchy integral subscript x end subscript superscript 0 end superscript d t equals not stretchy integral subscript 1 end subscript superscript x end superscript blank$ t³
dt – f ¢ (1) $not stretchy integral subscript 0 end subscript superscript x end superscript blank$ t² dt + f ¢¢ (2) $not stretchy integral subscript x end subscript superscript 3 end superscript blank$ t. dt, then the value of f ¢ (4) is :

If f : R → R is continuous and differentiable function such that $not stretchy integral subscript negative 1 end subscript superscript x end superscript blank$ f(t) dt + f¢¢¢ (3) $not stretchy integral subscript x end subscript superscript 0 end superscript d t equals not stretchy integral subscript 1 end subscript superscript x end superscript blank$ t³
dt – f ¢ (1) $not stretchy integral subscript 0 end subscript superscript x end superscript blank$ t² dt + f ¢¢ (2) $not stretchy integral subscript x end subscript superscript 3 end superscript blank$ t. dt, then the value of f ¢ (4) is :

Assertion : The refractive index of diamond is $square root of 6$ and that of liquid is $square root of 3$
If the light travels from diamond to the liquid, it will totally reflected when the angle of incidence is 30^o
Reason : $mu equals fraction numerator 1 over denominator sin invisible function application C end fraction$ where $mu$ is the refractive index of diamond with respect to liquid

Assertion : The refractive index of diamond is $square root of 6$ and that of liquid is $square root of 3$
If the light travels from diamond to the liquid, it will totally reflected when the angle of incidence is 30^o
Reason : $mu equals fraction numerator 1 over denominator sin invisible function application C end fraction$ where $mu$ is the refractive index of diamond with respect to liquid

physics-General

parallel

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