Question

# How much should 3x^{2} -5xy +7y^{2} +3 be increased to get 5x^{2}-7xy-3y^{4}+3x

Hint:

### Addition of polynomials.

○ Always take like terms together while performing addition.

○ In addition to polynomials only terms with the same coefficient are added.

## The correct answer is: Hence, the other term must add is - 3y4 - 7y2 + 2x2 - 2xy + 3x - 3.

### Answer:

- Step by step explanation:

○ Given:

Terms:

3x^{2} -5xy +7y^{2} +3

5x^{2}-7xy-3y^{4}+3x

○ Step 1:

○ Let A must be added to 3x^{2} -5xy +7y^{2} +3 to get 5x^{2}-7xy-3y^{4}+3x.

So,

A +3x^{2} -5xy +7y^{2} +3 = 5x^{2}-7xy-3y^{4}+3x

A = (5x^{2}-7xy-3y^{4}+3x ) - ( 3x^{2} -5xy +7y^{2} +3 )

A = - 3y^{4} - 7y^{2 }+ 5x^{2 }- 3x^{2}- 7xy + 5xy + 3x - 3

A = - 3y^{4} - 7y^{2 }+ 2x^{2 }- 2xy + 3x - 3

A = - 3y^{4} - 7y^{2 }+ 2x^{2 }- 2xy + 3x - 3

- Final Answer:

Hence, the other term must add is - 3y^{4} - 7y^{2 }+ 2x^{2 }- 2xy + 3x - 3.

^{2}-5xy +7y

^{2}+3

^{2}-7xy-3y

^{4}+3x

○ Step 1:

○ Let A must be added to 3x

^{2}-5xy +7y

^{2}+3 to get 5x

^{2}-7xy-3y

^{4}+3x.

So,

^{2}-5xy +7y

^{2}+3 = 5x

^{2}-7xy-3y

^{4}+3x

^{2}-7xy-3y

^{4}+3x ) - ( 3x

^{2}-5xy +7y

^{2}+3 )

^{4}- 7y

^{2 }+ 5x

^{2 }- 3x

^{2}- 7xy + 5xy + 3x - 3

^{4}- 7y

^{2 }+ 2x

^{2 }- 2xy + 3x - 3

^{4}- 7y

^{2 }+ 2x

^{2 }- 2xy + 3x - 3

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### In an academic contest correct answers earn 12 points and incorrect answers lose 5

points. In the final round, school A starts with 165 points and gives the same number

of correct and incorrect answers. School B starts with 65 points and gives no incorrect answers and the same number of correct answers as school A. The game ends with the two schools tied.

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¶The standard form of a linear equation in one variable is: ax + b = 0

Where,

The letters 'a' and 'b' are real numbers.

'a' and 'b' are both greater than zero.