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If 1 plus sin squared space theta equals 3 Sin backslash t h e t a Cos space theta then the solution set in  open parentheses 0 comma pi over 2 close parentheses is

Maths-General

  1. open curly brackets pi over 4 comma Cos to the power of negative 1 end exponent space 1 third close curly brackets
  2. open curly brackets pi over 4 comma Tan to the power of negative 1 end exponent space 1 half close curly brackets
  3. open curly brackets pi over 3 comma Tan to the power of negative 1 end exponent space 1 third close curly brackets
  4. open curly brackets pi over 6 comma Sin to the power of negative 1 end exponent space 1 third close curly brackets

    Answer:The correct answer is: open curly brackets pi over 4 comma Tan to the power of negative 1 end exponent space 1 half close curly brackets

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    A particle is moving along the circle x squared plus y squared equals a squared in anticlockwise direction. The x–y plane is a rough horizontal stationary surface. At the point left parenthesis a space cos theta comma space a space sin theta right parenthesis, the unit vector in the direction of friction on the particle is

    A particle is moving along the circle x squared plus y squared equals a squared in anticlockwise direction. The x–y plane is a rough horizontal stationary surface. At the point left parenthesis a space cos theta comma space a space sin theta right parenthesis, the unit vector in the direction of friction on the particle is

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    The equation square root of 3 sin space x plus cos space x equals 4 has

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    A man of mass 50 kg is pulling on a plank of mass 100 kg kept on a smooth floor as shown with force of 100 N. If both man & plank move together, find force of friction acting on man

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    In the following arrangement the system is initially at rest. The 5 kg block is now released. Assuming the pulleys and string to be massless and smooth, the acceleration of blocks is

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    Solutions in the given Interval: The value of theta satisfyingSin space 7 theta equals Sin space 4 theta minus Sin space theta text  in  end text 0 less than theta less than pi over 2 are

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    The area of the equilateral triangle which containing three coins of unity radius is

    In capital delta B C subscript 1 end subscript M; B M equals left parenthesis C subscript 1 end subscript M right parenthesis. cot invisible function application 3 0

    Þ B M equals square root of 3
    Þ Similarly, C N equals square root of 3and M N equals C subscript 1 end subscript C subscript 2 end subscript equals 1 plus 1 equals 2
    Hence, side B C equals square root of 3 plus square root of 3 plus 2 equals 2 left parenthesis 1 plus square root of 3 right parenthesis
    Þ Area of equilateral triangle
    equals fraction numerator square root of 3 over denominator 4 end fraction left square bracket 2 left parenthesis 1 plus square root of 3 right parenthesis right square bracket to the power of 2 end exponent=A B equals O A minus O B equals h left parenthesis cot invisible function application 1 5 to the power of o end exponent minus cot invisible function application 3 0 to the power of o end exponent right parenthesis sq units.

    The area of the equilateral triangle which containing three coins of unity radius is

    maths-General
    In capital delta B C subscript 1 end subscript M; B M equals left parenthesis C subscript 1 end subscript M right parenthesis. cot invisible function application 3 0

    Þ B M equals square root of 3
    Þ Similarly, C N equals square root of 3and M N equals C subscript 1 end subscript C subscript 2 end subscript equals 1 plus 1 equals 2
    Hence, side B C equals square root of 3 plus square root of 3 plus 2 equals 2 left parenthesis 1 plus square root of 3 right parenthesis
    Þ Area of equilateral triangle
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    General
    maths-

    If Sin space x times Sin space open parentheses 60 to the power of ring operator plus x close parentheses times Sin space open parentheses 60 to the power of ring operator minus x close parentheses equals 1 over 8 then x =

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    maths-

    If y plus Cos space theta equals Sin space theta has a real solution then

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    The curvesblank x to the power of 2 end exponent minus y to the power of 2 end exponent equals 5 blankandblank fraction numerator x to the power of 2 end exponent over denominator 18 end fraction plus fraction numerator y to the power of 2 end exponent over denominator 8 end fraction equals 1 blankcut each other at the common point at an angle

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    Block A of mass m is placed over a wedge B of same mass m. Assuming all surfaces to be smooth. The displacement of block A in 1 s if the system is released from rest is

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    physics-General
    General
    physics-

    The velocity-time graph of a particle in linear motion is shown. Both v and t are in SI units. What is the displacement of the particle from the origin after 8 s?

    text Displacement: = Area of upper trapezium  end text minus text  Area of lower trapezium end text
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    physics-General
    text Displacement: = Area of upper trapezium  end text minus text  Area of lower trapezium end text
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    physics-

    Two blocks A and B of equal mass m are connected through a massless string and arranged as shown in figure. Friction is absent everywhere. When the system is released from rest

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    If Cos space x plus Cos space y equals 1 and text  CosxCosy  end text equals 1 divided by 4 then the straight G subscript straight S straight S are

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    physics-General