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If fraction numerator a x over denominator cos invisible function application theta end fraction plus fraction numerator b y over denominator sin invisible function application theta end fraction equals open parentheses a squared minus b squared close parentheses,and fraction numerator a x sin invisible function application theta over denominator cos squared invisible function application theta end fraction minus fraction numerator b y cos invisible function application theta over denominator sin squared invisible function application theta end fraction equals 0,thenleft parenthesis a x right parenthesis to the power of 2 divided by 3 end exponent plus left parenthesis b y right parenthesis to the power of 2 divided by 3 end exponent equals

  1. open parentheses a squared minus b squared close parentheses to the power of 2 divided by 3 end exponent
  2. open parentheses a squared plus b squared close parentheses to the power of 2 divided by 3 end exponent
  3. open parentheses a squared plus b squared close parentheses to the power of 3 divided by 2 end exponent
  4. open parentheses a squared minus b squared close parentheses to the power of 3 divided by 2 end exponent

The correct answer is: open parentheses a squared minus b squared close parentheses to the power of 2 divided by 3 end exponent

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