Maths-
General
Easy

Question

If fraction numerator a x over denominator cos theta end fraction plus fraction numerator b y over denominator sin theta end fraction equals open parentheses a squared minus b squared close parentheses,and fraction numerator a x sin theta over denominator cos squared theta end fraction minus fraction numerator b y cos theta over denominator sin squared theta end fraction equals 0,thenleft parenthesis a x right parenthesis to the power of 2 divided by 3 end exponent plus left parenthesis b y right parenthesis to the power of 2 divided by 3 end exponent equals

  1. open parentheses a squared minus b squared close parentheses to the power of 2 divided by 3 end exponent
  2. open parentheses a squared plus b squared close parentheses to the power of 2 divided by 3 end exponent
  3. open parentheses a squared plus b squared close parentheses to the power of 3 divided by 2 end exponent
  4. open parentheses a squared minus b squared close parentheses to the power of 3 divided by 2 end exponent

The correct answer is: open parentheses a squared minus b squared close parentheses to the power of 2 divided by 3 end exponent


    fraction numerator a x over denominator cos theta end fraction plus fraction numerator b y over denominator sin theta end fraction equals open parentheses a squared minus b squared close parentheses space space space space space..... open parentheses 1 close parentheses
fraction numerator a x sin theta over denominator cos squared theta end fraction minus fraction numerator b y cos theta over denominator sin squared theta end fraction equals 0
fraction numerator a x sin theta over denominator cos squared theta end fraction equals fraction numerator b y cos theta over denominator sin squared theta end fraction
a x sin cubed theta equals b y cos cubed theta
therefore a x equals fraction numerator b y cos cubed theta over denominator sin cubed theta end fraction space space space space..... open parentheses 2 close parentheses

S u b s t i t u t i n g space e q u a t i o n space 2 space i n space 1 comma
fraction numerator b y cos cubed theta over denominator cos theta sin cubed theta end fraction plus fraction numerator b y over denominator sin theta end fraction equals open parentheses a squared minus b squared close parentheses
fraction numerator b y cos squared theta over denominator sin cubed theta end fraction plus fraction numerator b y over denominator sin theta end fraction equals open parentheses a squared minus b squared close parentheses
fraction numerator b y cos squared theta plus b y sin squared theta over denominator sin cubed theta end fraction equals open parentheses a squared minus b squared close parentheses
fraction numerator b y open parentheses cos squared theta plus sin squared theta close parentheses over denominator sin cubed theta end fraction equals open parentheses a squared minus b squared close parentheses
fraction numerator b y over denominator sin cubed theta end fraction equals open parentheses a squared minus b squared close parentheses
therefore b y equals open parentheses a squared minus b squared close parentheses sin cubed theta space space space space..... open parentheses 3 close parentheses

S u b s t i t u t i n g space t h e space v a l u e space o f space b y space i n space e q u a t i o n space 2 comma
a x equals fraction numerator b y cos cubed theta over denominator sin cubed theta end fraction
a x equals fraction numerator open parentheses a squared minus b squared close parentheses sin cubed theta cos cubed theta over denominator sin cubed theta end fraction space
therefore a x equals open parentheses a squared minus b squared close parentheses cos cubed theta space space space space..... open parentheses 4 close parentheses

N o w comma
open parentheses a x close parentheses to the power of 2 over 3 end exponent plus open parentheses b y close parentheses to the power of 2 over 3 end exponent
equals open parentheses open parentheses a squared minus b squared close parentheses cos cubed theta close parentheses to the power of 2 over 3 end exponent plus open parentheses open parentheses a squared minus b squared close parentheses sin cubed theta close parentheses to the power of 2 over 3 end exponent
equals open parentheses a squared minus b squared close parentheses to the power of 2 over 3 end exponent open parentheses cos squared theta plus sin squared theta close parentheses
equals open parentheses a squared minus b squared close parentheses to the power of 2 over 3 end exponent

    Related Questions to study

    General
    Maths-

    If A plus cos invisible function application B plus cos invisible function application C equals 0 then cos invisible function application 3 straight A plus cos invisible function application 3 straight B plus cos invisible function application 3 straight C

    If A plus cos invisible function application B plus cos invisible function application C equals 0 then cos invisible function application 3 straight A plus cos invisible function application 3 straight B plus cos invisible function application 3 straight C

    Maths-General
    General
    Maths-

    The value of fraction numerator 3 plus cot invisible function application 76 to the power of ring operator cot invisible function application 16 to the power of ring operator over denominator cot invisible function application 76 to the power of ring operator plus cot invisible function application 16 to the power of ring operator end fraction is

    The value of fraction numerator 3 plus cot invisible function application 76 to the power of ring operator cot invisible function application 16 to the power of ring operator over denominator cot invisible function application 76 to the power of ring operator plus cot invisible function application 16 to the power of ring operator end fraction is

    Maths-General
    General
    Maths-

    If  are four angles then sin invisible function application left parenthesis A minus B right parenthesis times cos invisible function application left parenthesis A plus B right parenthesis plus sin invisible function application left parenthesis B minus C right parenthesis cos invisible function application left parenthesis B plus C right parenthesis plus sin invisible function application left parenthesis C minus D right parenthesis.cos invisible function application left parenthesis C plus D right parenthesis plus sin invisible function application left parenthesis D minus A right parenthesis times cos invisible function application left parenthesis D plus A right parenthesis equals

    If  are four angles then sin invisible function application left parenthesis A minus B right parenthesis times cos invisible function application left parenthesis A plus B right parenthesis plus sin invisible function application left parenthesis B minus C right parenthesis cos invisible function application left parenthesis B plus C right parenthesis plus sin invisible function application left parenthesis C minus D right parenthesis.cos invisible function application left parenthesis C plus D right parenthesis plus sin invisible function application left parenthesis D minus A right parenthesis times cos invisible function application left parenthesis D plus A right parenthesis equals

    Maths-General
    parallel
    General
    Maths-

    If tan space theta subscript 1 comma tan space theta subscript 2 comma tan space theta subscript 3 and tan space theta subscript 4 are the roots of the equation x to the power of 4 minus x cubed sin space 2 beta plus x squared cos space 2 beta minus x cos space beta minus sin space beta equals 0  then tan space open parentheses theta subscript 1 plus theta subscript 2 plus theta subscript 3 plus theta subscript 4 close parentheses is equal to

    If tan space theta subscript 1 comma tan space theta subscript 2 comma tan space theta subscript 3 and tan space theta subscript 4 are the roots of the equation x to the power of 4 minus x cubed sin space 2 beta plus x squared cos space 2 beta minus x cos space beta minus sin space beta equals 0  then tan space open parentheses theta subscript 1 plus theta subscript 2 plus theta subscript 3 plus theta subscript 4 close parentheses is equal to

    Maths-General
    General
    chemistry-

    Formula of the following silicate anion is

    Formula of the following silicate anion is

    chemistry-General
    General
    chemistry-

    Sulphide mineral +CN to the power of minus rightwards arrow with straight O subscript 2 on top open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus 2 open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus plus Zn not stretchy rightwards arrow open square brackets Zn left parenthesis CN right parenthesis subscript 4 close square brackets to the power of 2 minus end exponent plus 2 M M

     can be

    Sulphide mineral +CN to the power of minus rightwards arrow with straight O subscript 2 on top open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus 2 open square brackets M left parenthesis CN right parenthesis subscript 2 close square brackets to the power of minus plus Zn not stretchy rightwards arrow open square brackets Zn left parenthesis CN right parenthesis subscript 4 close square brackets to the power of 2 minus end exponent plus 2 M M

     can be

    chemistry-General
    parallel
    General
    maths-

    The adjoining figure gives the road plan of lanes connecting two parallel roads AB and FJ Aman walking on the road AB takes a turn at random to reach the road FJ It is known that he reaches the road FJ from O by taking a straight line The chance that he moves on a straight line from the road AB to the road FJ is.

    The adjoining figure gives the road plan of lanes connecting two parallel roads AB and FJ Aman walking on the road AB takes a turn at random to reach the road FJ It is known that he reaches the road FJ from O by taking a straight line The chance that he moves on a straight line from the road AB to the road FJ is.

    maths-General
    General
    maths-

    The value of cos space y cos space left parenthesis pi divided by 2 minus x right parenthesis minus cos space left parenthesis pi divided by 2 minus y right parenthesis cos space x plus sin space y cos space left parenthesis pi divided by 2 minus x right parenthesis plus cos space x sin space left parenthesis pi divided by 2 minus y right parenthesis is Zero if

    The value of cos space y cos space left parenthesis pi divided by 2 minus x right parenthesis minus cos space left parenthesis pi divided by 2 minus y right parenthesis cos space x plus sin space y cos space left parenthesis pi divided by 2 minus x right parenthesis plus cos space x sin space left parenthesis pi divided by 2 minus y right parenthesis is Zero if

    maths-General
    General
    Maths-

    If sin space pi over 18 sin space fraction numerator 5 pi over denominator 18 end fraction sin space fraction numerator 7 pi over denominator 18 end fraction =

    If sin space pi over 18 sin space fraction numerator 5 pi over denominator 18 end fraction sin space fraction numerator 7 pi over denominator 18 end fraction =

    Maths-General
    parallel
    General
    Maths-

    The value of sin invisible function application 47 to the power of ring operator plus sin invisible function application 61 to the power of ring operator minus sin invisible function application 11 to the power of ring operator minus sin invisible function application 25 to the power of ring operatoris

    The value of sin invisible function application 47 to the power of ring operator plus sin invisible function application 61 to the power of ring operator minus sin invisible function application 11 to the power of ring operator minus sin invisible function application 25 to the power of ring operatoris

    Maths-General
    General
    Maths-

    If ABC is a triangle and tan space A over 2 comma tan space B over 2 comma tan space C over 2 are H.P then the minimum value of  cot space B over 2 is equal to

    If ABC is a triangle and tan space A over 2 comma tan space B over 2 comma tan space C over 2 are H.P then the minimum value of  cot space B over 2 is equal to

    Maths-General
    General
    Maths-

    If theta equals pi over 2 to the power of n plus 1 end exponent then cos space theta cos space 2 theta cos space 2 squared theta horizontal ellipsis cos space 2 to the power of n minus 1 end exponent theta is equal to

    If theta equals pi over 2 to the power of n plus 1 end exponent then cos space theta cos space 2 theta cos space 2 squared theta horizontal ellipsis cos space 2 to the power of n minus 1 end exponent theta is equal to

    Maths-General
    parallel
    General
    Maths-

    If A,B,C re in A.P and B equals pi over 4 then tan space A tan space B tan C =

    If A,B,C re in A.P and B equals pi over 4 then tan space A tan space B tan C =

    Maths-General
    General
    maths-

    If alpha comma beta comma gamma do not differ by a multiple of straight pi and iffraction numerator cos space left parenthesis alpha plus theta right parenthesis over denominator sin space left parenthesis beta plus gamma right parenthesis end fraction equals fraction numerator cos begin display style space end style left parenthesis beta plus theta right parenthesis over denominator sin begin display style space end style left parenthesis gamma plus alpha right parenthesis end fraction equals fraction numerator cos begin display style space end style left parenthesis gamma plus theta right parenthesis over denominator sin begin display style space end style left parenthesis alpha plus beta right parenthesis end fraction equals k Then k equals

    If alpha comma beta comma gamma do not differ by a multiple of straight pi and iffraction numerator cos space left parenthesis alpha plus theta right parenthesis over denominator sin space left parenthesis beta plus gamma right parenthesis end fraction equals fraction numerator cos begin display style space end style left parenthesis beta plus theta right parenthesis over denominator sin begin display style space end style left parenthesis gamma plus alpha right parenthesis end fraction equals fraction numerator cos begin display style space end style left parenthesis gamma plus theta right parenthesis over denominator sin begin display style space end style left parenthesis alpha plus beta right parenthesis end fraction equals k Then k equals

    maths-General
    General
    maths-

    From the figure AOC=

    From the figure AOC=

    maths-General
    parallel

    card img

    With Turito Academy.

    card img

    With Turito Foundation.

    card img

    Get an Expert Advice From Turito.

    Turito Academy

    card img

    With Turito Academy.

    Test Prep

    card img

    With Turito Foundation.