Maths-

#### If then =

Maths-General

#### Answer:The correct answer is:

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### Related Questions to study

physics-

#### The graph shown in the figure represents

Up to time slope of the graph is constant and after slope is zero the body travel with constant speed up to time and then stops

#### The graph shown in the figure represents

physics-General

Up to time slope of the graph is constant and after slope is zero the body travel with constant speed up to time and then stops

physics-

#### For the velocity-time graph shown in figure below the distance covered by the body in last two seconds of its motion is what fraction of the total distance covered by it in all the seven seconds

#### For the velocity-time graph shown in figure below the distance covered by the body in last two seconds of its motion is what fraction of the total distance covered by it in all the seven seconds

physics-General

physics-

#### A particle starts from rest at and undergoes an acceleration in with time in second which is as shownWhich one of the following plot represents velocity in time in second?

A particle starts from rest at

The equation of motion

The velocity for next 2 s

Hence, graph will be as shown.

The equation of motion

The velocity for next 2 s

Hence, graph will be as shown.

#### A particle starts from rest at and undergoes an acceleration in with time in second which is as shownWhich one of the following plot represents velocity in time in second?

physics-General

A particle starts from rest at

The equation of motion

The velocity for next 2 s

Hence, graph will be as shown.

The equation of motion

The velocity for next 2 s

Hence, graph will be as shown.

maths-

#### The area bounded by X- axis, x=1 and x=2 is

#### The area bounded by X- axis, x=1 and x=2 is

maths-General

maths-

#### The area bounded by y=3x and is

#### The area bounded by y=3x and is

maths-General

physics-

#### A body is at rest at . At , it starts moving in the positive -direction with a constant acceleration. At the same instant another body passes through moving in the positive -direction with a constant speed. The position of the first body is given by after time ‘’ and that of the second body by after the same time interval. Which of the following graphs correctly describes as a function of time ‘’

and

.This equation is of parabola

and

As graph shows possess minima at

.This equation is of parabola

and

As graph shows possess minima at

#### A body is at rest at . At , it starts moving in the positive -direction with a constant acceleration. At the same instant another body passes through moving in the positive -direction with a constant speed. The position of the first body is given by after time ‘’ and that of the second body by after the same time interval. Which of the following graphs correctly describes as a function of time ‘’

physics-General

and

.This equation is of parabola

and

As graph shows possess minima at

.This equation is of parabola

and

As graph shows possess minima at

maths-

General solution of is

General solution of is

maths-General

physics-

#### In the following graph, distance travelled by the body in metres is

Distance = Area covered between velocity and time axis

#### In the following graph, distance travelled by the body in metres is

physics-General

Distance = Area covered between velocity and time axis

physics-

#### A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point

Instantaneous velocity is given by the slope of the curve at that instant from the figure it is clear that slope of the curve is maximum at point ‘’

#### A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point

physics-General

Instantaneous velocity is given by the slope of the curve at that instant from the figure it is clear that slope of the curve is maximum at point ‘’

physics-

#### Velocity-time graph for a moving object is shown in the figure. Total displacement of the object during the time interval when there is non-zero acceleration and retardation is

Between time interval 20s the 4s, there is non-zero acceleration and retardation. Hence, distance travelled during this interval = Area between time interval 20 s to 40 s

#### Velocity-time graph for a moving object is shown in the figure. Total displacement of the object during the time interval when there is non-zero acceleration and retardation is

physics-General

Between time interval 20s the 4s, there is non-zero acceleration and retardation. Hence, distance travelled during this interval = Area between time interval 20 s to 40 s

physics-

#### Assertion : Owls can move freely during night.

Reason : They have large number of rods on their retina.

Owls can move freely during night, because they have large number of cones on their retina which help them to see in night.

#### Assertion : Owls can move freely during night.

Reason : They have large number of rods on their retina.

physics-General

Owls can move freely during night, because they have large number of cones on their retina which help them to see in night.

maths-

#### The value of k such that lies in the plane 2x-4y+z+7=0 is

#### The value of k such that lies in the plane 2x-4y+z+7=0 is

maths-General

maths-

#### The distance between the line and the plane is (units)

#### The distance between the line and the plane is (units)

maths-General

physics-

#### A the instant a motor bike starts from rest in a given direction, a car overtakes the motor bike, both moving in the same direction. The speed-time graphs for motor bike and car are represented by and respectively Then

Distance travelled by motor bike at s

(18)(60)=540 m

Distance travelled by car at s

=(18)(60)=720 m

Therefore, separation between them at s is 180m. Let, separation between them decreases to zero at time beyond 18s.

Hence, and

s beyond 18s or

Hence, s=27s from start and distant travelled by both is =m

(18)(60)=540 m

Distance travelled by car at s

=(18)(60)=720 m

Therefore, separation between them at s is 180m. Let, separation between them decreases to zero at time beyond 18s.

Hence, and

s beyond 18s or

Hence, s=27s from start and distant travelled by both is =m

#### A the instant a motor bike starts from rest in a given direction, a car overtakes the motor bike, both moving in the same direction. The speed-time graphs for motor bike and car are represented by and respectively Then

physics-General

Distance travelled by motor bike at s

(18)(60)=540 m

Distance travelled by car at s

=(18)(60)=720 m

Therefore, separation between them at s is 180m. Let, separation between them decreases to zero at time beyond 18s.

Hence, and

s beyond 18s or

Hence, s=27s from start and distant travelled by both is =m

(18)(60)=540 m

Distance travelled by car at s

=(18)(60)=720 m

Therefore, separation between them at s is 180m. Let, separation between them decreases to zero at time beyond 18s.

Hence, and

s beyond 18s or

Hence, s=27s from start and distant travelled by both is =m

physics-

#### A cyclist starts from the centre of a circular park of radius 1 km, reaches the edge of the park, then cycles along the circumference and returns to the point as shown in figure. If the round trip takes 10 min, the net displacement and average speed of the cyclist (in metre and kilometer per hour) are

Since, the initial position of cyclist coincides with final position, so his net displacement is zero.

#### A cyclist starts from the centre of a circular park of radius 1 km, reaches the edge of the park, then cycles along the circumference and returns to the point as shown in figure. If the round trip takes 10 min, the net displacement and average speed of the cyclist (in metre and kilometer per hour) are

physics-General

Since, the initial position of cyclist coincides with final position, so his net displacement is zero.