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If integrating factor of x open parentheses 1 minus x squared close parentheses d y plus open parentheses 2 x squared y minus y minus a x cubed close parentheses d x is e to the power of JPdx then P is

  1. fraction numerator 2 x squared minus a x cubed over denominator x open parentheses 1 minus x squared close parentheses end fraction
  2. 2 x cubed minus 1
  3. fraction numerator 2 x squared minus 1 over denominator a x cubed end fraction
  4. fraction numerator 2 x squared minus 1 over denominator x open parentheses 1 minus x squared close parentheses end fraction

The correct answer is: fraction numerator 2 x squared minus 1 over denominator x open parentheses 1 minus x squared close parentheses end fraction

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