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    Maths-
    General
    Easy

    Question

    If 'O'  is the Orthocentre of triangle A B C then O A equals

    1. R cos invisible function application A
    2. 2 R cos invisible function application A
    3. 2 R c o t invisible function application A
    4. R c o t invisible function application A

    The correct answer is: 2 R cos invisible function application A

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    In I n triangle A B C comma sum a cubed c o s invisible function application left parenthesis B minus C right parenthesis equals

    In I n triangle A B C comma sum a cubed c o s invisible function application left parenthesis B minus C right parenthesis equals

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    In triangle A B C comma left parenthesis a plus b right parenthesis cos invisible function application C plus left parenthesis b plus c right parenthesis cos invisible function application A plus left parenthesis c plus a right parenthesis cos invisible function application B equals

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    In triangle A B C comma sum 1 divided by a c o s squared invisible function application A divided by 2 equals

    In triangle A B C comma sum 1 divided by a c o s squared invisible function application A divided by 2 equals

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    In triangle A B C comma s squared t a n invisible function application A divided by 2 t a n invisible function application B divided by 2 t a n invisible function application C divided by 2 equals

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    In triangle A B C comma 4 R s sin invisible function application A divided by 2 space sin invisible function application B divided by 2 space sin invisible function application C divided by 2 equals

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    In A B C space comma space 4 R cos A divided by 2 space cos B divided by 2 space cos C divided by 2 equals

    In A B C space comma space 4 R cos A divided by 2 space cos B divided by 2 space cos C divided by 2 equals

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    In triangle A B C comma sum a cos invisible function application A equals

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    In capital delta A B C comma sum left parenthesis left parenthesis b squared minus c squared right parenthesis right parenthesis divided by a c o s invisible function application A equals

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    L t left parenthesis x rightwards arrow pi divided by 6 right parenthesis left parenthesis left parenthesis 3 s i n x minus √ 3 c o s x right parenthesis divided by left parenthesis 6 x minus pi right parenthesis right parenthesis equals

    L t left parenthesis x rightwards arrow pi divided by 6 right parenthesis left parenthesis left parenthesis 3 s i n x minus √ 3 c o s x right parenthesis divided by left parenthesis 6 x minus pi right parenthesis right parenthesis equals

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    If L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis left parenthesis c o s invisible function application 4 x plus a c o s invisible function application 2 x plus b right parenthesis divided by x to the power of 4 right parenthesis is finite then the values of a,b are respectively

    If L t left parenthesis x rightwards arrow 0 right parenthesis left parenthesis left parenthesis c o s invisible function application 4 x plus a c o s invisible function application 2 x plus b right parenthesis divided by x to the power of 4 right parenthesis is finite then the values of a,b are respectively

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    If f left parenthesis x right parenthesis equals x t a n left parenthesis negative 1 right parenthesis invisible function application x then l i m subscript left parenthesis x rightwards arrow 1 right parenthesis   left parenthesis f left parenthesis x right parenthesis minus f left parenthesis 1 right parenthesis right parenthesis divided by left parenthesis x minus 1 right parenthesis equals

    If f left parenthesis x right parenthesis equals x t a n left parenthesis negative 1 right parenthesis invisible function application x then l i m subscript left parenthesis x rightwards arrow 1 right parenthesis   left parenthesis f left parenthesis x right parenthesis minus f left parenthesis 1 right parenthesis right parenthesis divided by left parenthesis x minus 1 right parenthesis equals

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    If f colon R rightwards arrow R be a positive increasing function with L t left parenthesis x rightwards arrow infinity right parenthesis space space left parenthesis f left parenthesis 3 x right parenthesis right parenthesis divided by left parenthesis f left parenthesis x right parenthesis right parenthesis equals 1 spacethen L t left parenthesis x rightwards arrow infinity right parenthesis space space left parenthesis f left parenthesis 2 x right parenthesis right parenthesis divided by left parenthesis f left parenthesis x right parenthesis right parenthesis

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    L t left parenthesis n rightwards arrow infinity right parenthesis left square bracket 1 divided by n squared s e c squared 1 divided by n squared plus 2 divided by n squared s e c squared 4 divided by n squared plus midline horizontal ellipsis. plus 1 divided by n s e c squared 1 right square bracket equals

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    L t left parenthesis n rightwards arrow infinity right parenthesis left parenthesis 1 plus 2 to the power of 4 plus 3 to the power of 4 plus midline horizontal ellipsis plus n to the power of 4 right parenthesis divided by n to the power of 5 minus L t left parenthesis 1 plus 2 cubed plus 3 cubed plus.. plus n cubed right parenthesis divided by n to the power of 4 equals

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    If f left parenthesis x plus y right parenthesis equals f left parenthesis x right parenthesis f left parenthesis y right parenthesis plus x comma y spaceand f left parenthesis 5 right parenthesis equals 2 comma f to the power of apostrophe left parenthesis 0 right parenthesis equals 3 then f to the power of apostrophe left parenthesis 5 right parenthesis is

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