Maths-

General

Easy

Question

# (ii) x^{2} + y^{2}, 2x^{2}, –3y^{2}, 3x^{2} – 4y^{2}

## The correct answer is: 3x2 – 6y2

### Answer:

○ The concept used in this question is of addition of polynomials.

○ Arrange the term in the decreasing order of their power.

○ To add polynomials simply add any like terms together.

○ Like terms are terms whose variables and exponents are the same

- Step by step explanation:

○ Given:

Expression: x^{2} + y^{2}, 2x^{2}, –3y^{2}, 3x^{2} – 4y^{2}

○ Step 1:

○ Simplify the expression.

∴ ( x^{2} + y^{2}) + ( 2x^{2}) + (–3y^{2} ) + ( – 4y^{2} )

○ Step 2:

○ Perform simple addition of like terms

x^{2} + y^{2} + 2x^{2} – 3y^{2} – 4y^{2}

x^{2 }+ 2x^{2} + y^{2} – 3y^{2} – 4y^{2}

3x^{2 }– 6y^{2}

- Final Answer:

3x^{2 }– 6y^{2}

^{2}+ y

^{2}+ 2x

^{2}– 3y

^{2}– 4y

^{2}

^{2 }+ 2x

^{2}+ y

^{2}– 3y

^{2}– 4y

^{2}

^{2 }– 6y

^{2}

^{2 }– 6y

^{2}

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