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In straight triangle A B C comma open parentheses fraction numerator b minus c over denominator a end fraction close parentheses sin invisible function application open parentheses fraction numerator B plus C over denominator 2 end fraction close parentheses equals

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  1. sin invisible function application open parentheses fraction numerator A minus B over denominator 2 end fraction close parentheses
  2. cos invisible function application open parentheses fraction numerator A minus B over denominator 2 end fraction close parentheses
  3. cos invisible function application open parentheses fraction numerator B minus C over denominator 2 end fraction close parentheses
  4. sin invisible function application open parentheses fraction numerator B minus C over denominator 2 end fraction close parentheses

    Answer:The correct answer is: sin invisible function application open parentheses fraction numerator B minus C over denominator 2 end fraction close parentheses

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