Maths-
General
Easy
Question
Lawren has $1000 in a saving account. He wants to save at least $400 before winter. He withdraws $50 every week for daily requirements. Write an inequality that represents Lawren’s situation.
- 1000+50w
400 - 1000-50w
400 - 1000 + 50w
400 - 1000-50w
400
Hint:
We are given that Lawren has $1000 in a saving account. He withdraws $50 per week for daily requirements. He has to save at least $400 dollars. We have to write the inequality of the above equation.
The correct answer is: 1000+50w
400
Total amount in saving account is $1000.
Amount withdraw per week is $50.
The amount he has to save the least is $400.
Let the number of weeks he deduct the amount till he reached the balance of at least $400 be denoted by w.
The balance should be at least $400. So, the amount can be greater than or equal to this quantity.
Amount
$400
The amount $1000 is constant.
The amount deducted till he reached the least balance is $50×w i.e. 50w. The amount is deducted, so we will subtract it from the saved amount.
The inequality will be
1000 - 50w
400
For such questions, we have to see which quantity is constant and variable. We have be careful about the words like “at least”, “at most”, etc.
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