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Let A(2,3,5), B(-1,3,2), C left parenthesis lambda comma 5 comma mu right parenthesis are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following Projection of AB on BC is

  1. fraction numerator 8 square root of 3 over denominator 11 end fraction
  2. fraction numerator negative 8 square root of 3 over denominator 11 end fraction
  3. negative 48
  4. 48

The correct answer is: fraction numerator negative 8 square root of 3 over denominator 11 end fraction

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Let A(2,3,5), B(-1,3,2),  are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following The value of  is equal to

Let A(2,3,5), B(-1,3,2),  are the vertices of a triangle and its median through A (i.e.) AD is equally inclined to the coordinate axes On the basis of the above information answer the following The value of  is equal to

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Let two planes P subscript 1 colon 2 x minus y plus z equals 2 and P subscript 2 colon x plus 2 y minus z equals 3 are given On the basis of the above information, answer the following question: The image of plane P1 in the plane mirror P2 is

 Therefore, the equation becomes 7x-y+2z=9.

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 Therefore, the equation becomes 7x-y+2z=9.

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Let two planes P subscript 1 colon 2 x minus y plus z equals 2 and P subscript 2 colon x plus 2 y minus z equals 3 are given On the basis of the above information, answer the following question: The equation of the bisector of angle of the planes P1 and P2 which not containing origin is

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-> 3x +y = 5.

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P subscript 1 colon 2 x minus y plus z equals 2 + P subscript 2 colon x plus 2 y minus z equals 3
-> 3x +y = 5.

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Let f left parenthesis x right parenthesis equals sin invisible function application x integral subscript 1 superscript x   cos invisible function application t d t plus 2 integral subscript 0 superscript x   t d t plus cos squared invisible function application x minus x squared then area bounded by x. f(x), and x=0, x=5 with x axis, is (in sq units)

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(6,6) is a point on the circle x to the power of 2 end exponent plus y to the power of 2 end exponent minus 4 x minus 6 y minus 12 equals 0 by translation of origin to a certain point the translated equation is x to the power of 2 end exponent plus y to the power of 2 end exponent equals 25 the new co-ordinates of (6,6) are

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The locus of points from which lengths of tangents to the two circles x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x plus 3 equals 0 comma x squared plus y squared minus 6 x plus 5 equals 0 are in the ratio 2 : 3 is a circle with centre

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