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Let f colon open square brackets 1 half comma 1 close square brackets not stretchy rightwards arrow left square bracket negative 1 comma 1 right square bracket is given byf left parenthesis x right parenthesis equals 4 x cubed minus 3 x text  then  end text f to the power of negative 1 end exponent left parenthesis x right parenthesis text  is given by  end text

Maths-General

  1. cos invisible function application open square brackets 1 third cos to the power of negative 1 end exponent invisible function application x close square brackets
  2. 3 sin to the power of negative 1 end exponent invisible function application left parenthesis cos invisible function application x right parenthesis
  3. 3 cos invisible function application open parentheses sin to the power of negative 1 end exponent invisible function application x close parentheses
  4. sin invisible function application open parentheses 1 third cos to the power of negative 1 end exponent invisible function application x close parentheses

    Answer:The correct answer is: cos invisible function application open square brackets 1 third cos to the power of negative 1 end exponent invisible function application x close square brackets

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    Related Questions to study

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    The domain of the function  f left parenthesis x right parenthesis equals fraction numerator tan invisible function application 2 x over denominator 6 cos invisible function application x plus 2 sin invisible function application 2 x end fraction text  is  end text

    The domain of the function  f left parenthesis x right parenthesis equals fraction numerator tan invisible function application 2 x over denominator 6 cos invisible function application x plus 2 sin invisible function application 2 x end fraction text  is  end text

    maths-General
    General
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    2.1 squared plus 3.2 squared plus 4.3 squared plus midline horizontal ellipsis horizontal ellipsis plus left parenthesis n plus 1 right parenthesis n squared equals

    2.1 squared plus 3.2 squared plus 4.3 squared plus midline horizontal ellipsis horizontal ellipsis plus left parenthesis n plus 1 right parenthesis n squared equals

    maths-General
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    If f left parenthesis x right parenthesis equals fraction numerator 10 to the power of x minus 10 to the power of negative x end exponent over denominator 10 to the power of x plus 10 to the power of negative x end exponent end fraction text  then  end text f to the power of negative 1 end exponent left parenthesis x right parenthesis equals

    If f left parenthesis x right parenthesis equals fraction numerator 10 to the power of x minus 10 to the power of negative x end exponent over denominator 10 to the power of x plus 10 to the power of negative x end exponent end fraction text  then  end text f to the power of negative 1 end exponent left parenthesis x right parenthesis equals

    maths-General
    General
    physics

    A particle is thrown in upward direction with initial velocity V0 It crosses point P at height  h at time t1 and t2 so t1 t2 ……..

    A particle is thrown in upward direction with initial velocity V0 It crosses point P at height  h at time t1 and t2 so t1 t2 ……..

    physicsGeneral
    General
    maths-

    If f left parenthesis x right parenthesis equals fraction numerator e to the power of x plus e to the power of negative x end exponent over denominator 2 end fraction ,then the inverse function of f left parenthesis x right parenthesis text  is  end text

    If f left parenthesis x right parenthesis equals fraction numerator e to the power of x plus e to the power of negative x end exponent over denominator 2 end fraction ,then the inverse function of f left parenthesis x right parenthesis text  is  end text

    maths-General
    General
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    The domain of f left parenthesis x right parenthesis equals fraction numerator 1 over denominator vertical line sin invisible function application x vertical line plus sin invisible function application x end fraction text  is  end text

    The domain of f left parenthesis x right parenthesis equals fraction numerator 1 over denominator vertical line sin invisible function application x vertical line plus sin invisible function application x end fraction text  is  end text

    maths-General
    General
    physics

    Ball A is thrown in upward from the top of a tower of height h. At the same time ball B starts to fall from that point. When A comes to the top of the tower, B reaches the ground. Find the  time to reach maximum height for A.

    Ball A is thrown in upward from the top of a tower of height h. At the same time ball B starts to fall from that point. When A comes to the top of the tower, B reaches the ground. Find the  time to reach maximum height for A.

    physicsGeneral
    General
    physics

    In the figure Velocity (V)not stretchy rightwards arrow position graph is given. Find the true equation.

    In the figure Velocity (V)not stretchy rightwards arrow position graph is given. Find the true equation.

    physicsGeneral
    General
    maths-

    The domain of the function f left parenthesis x right parenthesis equals square root of cosec space x minus 1 end root text  is  end text

    The domain of the function f left parenthesis x right parenthesis equals square root of cosec space x minus 1 end root text  is  end text

    maths-General
    General
    maths-

    If f left parenthesis x right parenthesis equals x squared plus x comma x equals 10 comma delta x equals 0.1 observe the following
    text  l)  end text delta f equals 2.11
    text  II)  end text d f equals 2.1
    text  III) Relative error in  end text x text  is  end text 1
    The true statements are

    If f left parenthesis x right parenthesis equals x squared plus x comma x equals 10 comma delta x equals 0.1 observe the following
    text  l)  end text delta f equals 2.11
    text  II)  end text d f equals 2.1
    text  III) Relative error in  end text x text  is  end text 1
    The true statements are

    maths-General
    General
    maths-

    Statement I :f colon A not stretchy rightwards arrow B text  is one - one and  end text g colon B not stretchy rightwards arrow C text  is a one-one function, then gof  end text colon A not stretchy rightwards arrow C is one - one
    Statement II :text  If  end text f colon A not stretchy rightwards arrow B comma g colon B not stretchy rightwards arrow A are two functions such that g o f equals I subscript A text  and  end text fog equals I subscript B comma text  then  end text f equalsg to the power of negative 1 end exponent
    Staatement III : f left parenthesis x right parenthesis equals sec squared invisible function application x minus tan squared invisible function application x g left parenthesis x right parenthesis equals cosec squared invisible function application x minus cot squared invisible function application x comma text  then  end text f equals g

    Which of the above statement/s is/are true.

    Statement I :f colon A not stretchy rightwards arrow B text  is one - one and  end text g colon B not stretchy rightwards arrow C text  is a one-one function, then gof  end text colon A not stretchy rightwards arrow C is one - one
    Statement II :text  If  end text f colon A not stretchy rightwards arrow B comma g colon B not stretchy rightwards arrow A are two functions such that g o f equals I subscript A text  and  end text fog equals I subscript B comma text  then  end text f equalsg to the power of negative 1 end exponent
    Staatement III : f left parenthesis x right parenthesis equals sec squared invisible function application x minus tan squared invisible function application x g left parenthesis x right parenthesis equals cosec squared invisible function application x minus cot squared invisible function application x comma text  then  end text f equals g

    Which of the above statement/s is/are true.

    maths-General
    General
    physics

    A particle is moving in a straight line with initial velocity of 10 ms-1 A graph of acceleration not stretchy rightwards arrow tine of the particle is given in the figure. Find velocity at t=10s.

    A particle is moving in a straight line with initial velocity of 10 ms-1 A graph of acceleration not stretchy rightwards arrow tine of the particle is given in the figure. Find velocity at t=10s.

    physicsGeneral
    General
    physics-

    A glass capillary sealed at the upper end is of length 0.11 m and internal diameter 2 cross times 1 0 to the power of negative 5 end exponentm. The tube is immersed vertically into a liquid of surface tension 5.06 cross times 1 0 to the power of negative 2 end exponent N/m. To what length has the capillary to be immersed so that the liquid level inside and outside the capillary becomes the same?

    P subscript i n end subscript equals P subscript 0 end subscript But P subscript 0 end subscript L equals P subscript i n end subscript open parentheses L minus x close parentheses

    A glass capillary sealed at the upper end is of length 0.11 m and internal diameter 2 cross times 1 0 to the power of negative 5 end exponentm. The tube is immersed vertically into a liquid of surface tension 5.06 cross times 1 0 to the power of negative 2 end exponent N/m. To what length has the capillary to be immersed so that the liquid level inside and outside the capillary becomes the same?

    physics-General
    P subscript i n end subscript equals P subscript 0 end subscript But P subscript 0 end subscript L equals P subscript i n end subscript open parentheses L minus x close parentheses
    General
    physics-

    Water flows through a frictionless duct with a cross-section varying as shown in fig. . Pressure p at points along the axis is represented by: A resume water to be non-viscour

    Application of Bernoulli’s theorem

    Water flows through a frictionless duct with a cross-section varying as shown in fig. . Pressure p at points along the axis is represented by: A resume water to be non-viscour

    physics-General
    Application of Bernoulli’s theorem
    General
    physics-

    A cubical block of wood 10 cm on a side floats at the interface between oil and water with its lower surface horizontal and 4 cm below the interface. The density of oil is 0.6 g c m to the power of negative 3 end exponent. The mass of block is

    Weight of block
    = Weight of displaced oil + Weight of displaced water
    Þ m g equals V subscript 1 end subscript rho subscript 0 end subscript g plus V subscript 2 end subscript rho subscript W end subscript g
    Þ m equals left parenthesis 10 cross times 10 cross times 6 right parenthesis cross times 0.6 plus left parenthesis 10 cross times 10 cross times 4 right parenthesis cross times 1= 760 gm

    A cubical block of wood 10 cm on a side floats at the interface between oil and water with its lower surface horizontal and 4 cm below the interface. The density of oil is 0.6 g c m to the power of negative 3 end exponent. The mass of block is

    physics-General
    Weight of block
    = Weight of displaced oil + Weight of displaced water
    Þ m g equals V subscript 1 end subscript rho subscript 0 end subscript g plus V subscript 2 end subscript rho subscript W end subscript g
    Þ m equals left parenthesis 10 cross times 10 cross times 6 right parenthesis cross times 0.6 plus left parenthesis 10 cross times 10 cross times 4 right parenthesis cross times 1= 760 gm