Question

# Let the eleven letters .....,K denote an arbitrary permutation of the integers (1, 2,.....11), then

- Necessarily zero
- Always odd
- Always even
- None of these

## The correct answer is: Always even

### Given set of numbers is {1, 2,....11} in which 5 are even six are odd, which demands that in the given product it is not possible to arrange to subtract only even number from odd numbers. There must be at least one factor involving subtraction of an odd number form another odd number. So at least one of the factors is even. Hence product is always even

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