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Lt subscript n not stretchy rightwards arrow straight infinity end subscript sum from n equals 1 to n of   open square brackets fraction numerator 1 over denominator left parenthesis 2 n plus 1 right parenthesis left parenthesis 2 n plus 3 right parenthesis end fraction close square brackets

  1. 6
  2. 1
  3. 1 over 6
  4. 0

hintHint:

It is sequence, it can be seen easily that it tends to 0.In this question, we have to find value of  Lt subscript n not stretchy rightwards arrow straight infinity end subscript sum from n equals 1 to n of   open square brackets fraction numerator 1 over denominator left parenthesis 2 n plus 1 right parenthesis left parenthesis 2 n plus 3 right parenthesis end fraction close square brackets.

The correct answer is: 1 over 6


    Lt subscript n not stretchy rightwards arrow straight infinity end subscript sum from n equals 1 to n of   open square brackets fraction numerator 1 over denominator left parenthesis 2 n plus 1 right parenthesis left parenthesis 2 n plus 3 right parenthesis end fraction close square brackets
    Lt subscript n not stretchy rightwards arrow straight infinity end subscript sum from n equals 1 to n of   open square brackets fraction numerator 2 n plus 3 space minus 2 n minus 1 over denominator left parenthesis 2 n plus 1 right parenthesis left parenthesis 2 n plus 3 right parenthesis end fraction close square brackets cross times 1 half space equals space 1 half cross times Lt subscript n not stretchy rightwards arrow straight infinity end subscript sum from n equals 1 to n of   open square brackets fraction numerator 1 over denominator left parenthesis 2 n plus 1 right parenthesis end fraction close square brackets space minus 1 half cross times Lt subscript n not stretchy rightwards arrow straight infinity end subscript sum from n equals 1 to n of   open square brackets fraction numerator 1 over denominator left parenthesis 2 n plus 3 right parenthesis end fraction close square brackets
    1 half cross times Lt subscript n not stretchy rightwards arrow straight infinity end subscript sum from n equals 1 to n of   open square brackets fraction numerator 1 over denominator left parenthesis 2 n plus 1 right parenthesis end fraction close square brackets space minus   open square brackets fraction numerator 1 over denominator left parenthesis 2 n plus 3 right parenthesis end fraction close square brackets space space space space
sum from n equals 1 to n of   open square brackets fraction numerator 1 over denominator left parenthesis 2 n plus 1 right parenthesis end fraction close square brackets space minus   open square brackets fraction numerator 1 over denominator left parenthesis 2 n plus 3 right parenthesis end fraction close square brackets space equals space   open square brackets fraction numerator 1 over denominator left parenthesis 3 right parenthesis end fraction close square brackets space minus   open square brackets fraction numerator 1 over denominator left parenthesis 5 right parenthesis end fraction close square brackets plus   open square brackets fraction numerator 1 over denominator left parenthesis 5 right parenthesis end fraction close square brackets space minus   open square brackets fraction numerator 1 over denominator left parenthesis 7 right parenthesis end fraction close square brackets..... space equals open square brackets fraction numerator 1 over denominator left parenthesis 3 right parenthesis end fraction close square brackets
    1 half cross times Lt subscript n not stretchy rightwards arrow straight infinity end subscript   open square brackets fraction numerator 1 over denominator left parenthesis 3 right parenthesis end fraction close square brackets space
    On substituting, We get
    1 half cross times Lt subscript n not stretchy rightwards arrow straight infinity end subscript   open square brackets fraction numerator 1 over denominator left parenthesis 3 right parenthesis end fraction close square brackets space space equals space 1 over 6

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