Maths-
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Question

Lt subscript x not stretchy rightwards arrow straight infinity end subscript space fraction numerator 8 vertical line x vertical line plus 3 x over denominator 3 vertical line x vertical line minus 2 x end fraction

  1. 11
  2. 10
  3. 8
  4. 5

Hint:

In the question we know that open vertical bar x close vertical bar has two values of x positive and negative here we will take x as positive as limit has positive infinity.

The correct answer is: 11


    Lt subscript x not stretchy rightwards arrow straight infinity end subscript space fraction numerator 8 vertical line x vertical line plus 3 x over denominator 3 vertical line x vertical line minus 2 x end fraction
    open vertical bar x close vertical bar equals open curly brackets table attributes columnalign left end attributes row cell x space space space comma space x greater or equal than 0 end cell row cell negative x comma space x less than 0 end cell end table close
t a k i n g space x space p o s i t i v e comma
limit as x rightwards arrow infinity of fraction numerator 8 x plus 3 x over denominator 3 x minus 2 x end fraction equals limit as x rightwards arrow infinity of fraction numerator 11 x over denominator x end fraction equals 11

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