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Mathematics

Grade5

Easy

Question

131 × 20=_____.

2,690
2,620
2,900
2,700

hint Hint:

In this question we have to multiply as three-digit number with a two-digit number. We can use the distributive law to do this question. Distributive law relates multiplication and addition as follows: $a left parenthesis b plus c plus d right parenthesis equals left parenthesis a cross times b right parenthesis plus left parenthesis a cross times c right parenthesis plus left parenthesis a cross times space d right parenthesis$ .This law shows that first adding some numbers and the multiplying the sum by some numbers gives same result as first multiplying each number by separately with the number and then adding them

The correct answer is: 2,620

Step1: We have to use the standard algorithm to find the multiplication so we will first break the one number into small numbers that can be easily multiplied to get the result. So, we will divide $131$ as follows:
$131 equals 100 plus 30 plus 1$
Step2: Now we will use the distributive property to multiply this:
$20 cross times left parenthesis 100 plus 30 plus 1 right parenthesis equals left parenthesis 20 cross times 100 right parenthesis plus left parenthesis 20 cross times 30 right parenthesis plus left parenthesis 20 cross times 1 right parenthesis$
Step3: Now we will do simple multiplication of which are as follows:
$20 cross times 100 equals 2 comma 000 20 cross times 30 equals 600 20 cross times 1 equals 20$
Step4: Now we have to add these numbers.
$left parenthesis 20 cross times 100 right parenthesis plus left parenthesis 20 cross times 30 right parenthesis plus left parenthesis 20 cross times 1 right parenthesis equals 2 comma 000 plus 600 plus 20$
=> $2620$ .
So, the answer of the multiplication of $131 space cross times space 20$ is $2620$ .

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