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Mathematics

Grade9

Easy

Question

Find the area of the sector (in square cm.) whose radius and length of arc are 6 cm and 20 cm, respectively.

50
55
40
60

hint Hint:

$a r e a space o f space t h e space a r c space equals space fraction numerator r a d i u s cross times a r c space l e n g t h over denominator 2 end fraction equals fraction numerator l r over denominator 2 end fraction$

The correct answer is: 60

$g i v e n space r a d i u s space left parenthesis r right parenthesis space equals space 6 space c m space a n d space l e n g t h space o s f space a r c left parenthesis l right parenthesis space equals space 20 c m w e space k n o w space t h a t space a r e a space o f space t h e space a r c space equals space fraction numerator r a d i u s cross times a r c space l e n g t h over denominator 2 end fraction equals fraction numerator l r over denominator 2 end fraction s o space a r e a space o f space a r c space equals space fraction numerator 20 c m space cross times space 6 c m over denominator 2 end fraction equals space 20 c m cross times 3 c m space equals space 60 c m squared space a n s w e r a r e a space o f space a r c space equals space 60 space s q u a r e space c m$

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