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Mathematics

Grade9

Easy

Question

Find the area of the semi-circle.

3.14
6.28
12.56
9.42

hint Hint:

Area of the sector $equals fraction numerator A n g l e o f sec invisible function application t o r over denominator 360 to the power of 0 end exponent end fraction cross times pi r to the power of 2 end exponent$

The correct answer is: 6.28

Area of semicircle = ( $fraction numerator 180 over denominator 360 end fraction$ ) ×3.14 × 2×2 = 6.28

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