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Mathematics

Grade9

Easy

Question

If a circle has an area of 120 $pi$ , then the area of a sector with an angle of 36° is equal to

60 $π$
36 $π$
24 $π$
12 $π$

hint Hint:

$A equals pi r to the power of 2 end exponent$
Area of the sector $equals fraction numerator A n g l e o f sec invisible function application t o r over denominator 360 to the power of 0 end exponent end fraction cross times pi r to the power of 2 end exponent$

The correct answer is: 12 $pi$

$A equals pi r to the power of 2 end exponent equals 120 pi$
Area of the sector $equals fraction numerator A n g l e o f sec invisible function application t o r over denominator 360 to the power of 0 end exponent end fraction cross times pi r to the power of 2 end exponent$
= $fraction numerator 36 to the power of 0 end exponent over denominator 360 to the power of 0 end exponent end fraction cross times pi r to the power of 2 end exponent$
= $fraction numerator 36 to the power of 0 end exponent over denominator 360 to the power of 0 end exponent end fraction cross times 120 pi$
= $12 pi$

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