Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Mathematics

Grade9

Easy

Question

If angle $angle B O X$ is $120 degree$ , what is the area of sector BOX in square meters? (radius = 15 m)

225 $π$
115 $π$
15 $π$
75 $π$

hint Hint:

Area of the sector $equals fraction numerator A n g l e o f sec invisible function application t o r over denominator 360 to the power of 0 end exponent end fraction cross times pi r to the power of 2 end exponent$

The correct answer is: 75 $pi$

To find the area of a sector, simply multiply the total area of the circle by the fraction of the part you are looking at.
In this case, our area will come from the following:
$A equals pi r to the power of 2 end exponent equals pi cross times left parenthesis 15 m right parenthesis to the power of 2 end exponent equals 225 pi m to the power of 2 end exponent$
To find the fractional part of the circle we care about, take the number of degrees in $angle B O X$ over the total number of degrees in a circle $360 to the power of ring operator end exponent$ ):
$fraction numerator 120 over denominator 360 end fraction equals fraction numerator 1 over denominator 3 end fraction$
So, we find our answer by multiplying these two parts together:
$225 pi m to the power of 2 end exponent cross times fraction numerator 1 over denominator 3 end fraction equals 75 pi m to the power of 2 end exponent$

Related Questions to study

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.