404c_(4)-c_(4)*c_(1)+2024-1014= -Turito

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General

Easy

Maths-

$404 C subscript 4 end subscript minus C subscript 4 end subscript. C subscript 1 end subscript plus 2024 minus 1014 equals$

Maths-General

$(101)^{3}$
$(101)^{4}$
$(202)^{3}$
$(202)^{4}$

Answer:The correct answer is: $left parenthesis 101 right parenthesis to the power of 4 end exponent$

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Standard Results

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A: If the term independent of $x$ in the expansion of $left parenthesis square root of x minus fraction numerator n over denominator x to the power of 2 end exponent end fraction right parenthesis to the power of 10 end exponent$ is 405, then n=
$B$ : If the third term in the expansion of $left parenthesis fraction numerator 1 over denominator n end fraction plus n to the power of l o g subscript n end subscript 10 end exponent right parenthesis to the power of 5 end exponent$ is 1000, then n=(here n<10)
$C$ : If in the binomial expansion of $left parenthesis 1 plus x right parenthesis to the power of n end exponent comma$ the coefficients of 5^th $comma$ 6^th and 7^th terms are in A.P then n= [Arranging the values of n in ascending order]

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$B$ : If the third term in the expansion of $left parenthesis fraction numerator 1 over denominator n end fraction plus n to the power of l o g subscript n end subscript 10 end exponent right parenthesis to the power of 5 end exponent$ is 1000, then n=(here n<10)
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